C#画一个非空心的菱形？

答案：
using System;
using System.Collections.Generic;
using System.Text;

namespace temp
{
    class Class9
    {
        static void Main(string[] args)
        {
            Console.WriteLine("请输入菱形边长");
            string s = Console.ReadLine();
            int i = 0;
            try
            {
                i = int.Parse(s);
            }
            catch
            {
                Console.WriteLine("请输入大于2的数");
            }
            if (i < 2)
            {
                Console.WriteLine("请输入大于2的数");
            }
            for (int j = 1; j <= i; j++)//打印上半个菱形
            {
                for (int k = 0; k < i - j; k++)
                {
                    Console.Write(" ");
                }
                Console.Write("*");
                if (j == 1)
                {
                    Console.Write("\n");
                    continue;
                }
                for (int k = 1; k <= (j - 1) * 2 - 1; k++)
                {
                    Console.Write(" ");
                }
                Console.Write("*\n");

            }
            for (int j = 1; j <= i - 1; j++)//下半个菱形比上半个少1行
            {

                for (int k = 0; k < j; k++)
                {
                    Console.Write(" ");
                }
                Console.Write("*");
                if (j == i - 1)
                {
                    Console.Write("\n");
                    continue;
                }

                for (int k = 1; k <= (i - j - 1) * 2 - 1; k++)
                {
                    Console.Write(" ");
                }
                Console.Write("*\n");
            }
        }

    }


这是一个由用户定义长度的空心菱形
package com.cilery.com;

public class Sqr {

public static void main(String[] args) {

Sqr sqr = new Sqr();
sqr.doSqr(3);
}

public void doSqr(int l) {
String sqr[][] = new String[2 * l + 1][2 * l + 1];
for (int i = 0; i < 2 * l + 1; i++) {
for (int j = 0; j < 2 * l + 1; j++)
sqr[i][j] = " ";
}
for (int i = 0; i < 2 * l + 1; i++) {
for (int j = 0; j < 2 * l + 1; j++) {
if ((i + j == l) || (i + j == l + 2 * l) || i - j == l|| i - j == l - 2 * l)
sqr[i][j] = "@";
}
}
for (int i = 0; i < 2 * l + 1; i++) {
{
for (int j = 0; j < 2 * l + 1; j++)
System.out.print(sqr[i][j]);
}
System.out.print("\n");
}
}
}

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