jQuery + json 实现的简易Ajax调用
Userservlet.java代码
package com.iss.servlet;
import org.json.JSONException;
import org.json.JSONObject;
import com.iss.pojo.User;
import com.iss.util.JSONUtil;
public class UserServlet extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doPost(request, response);
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html;charset=utf-8");
//list 添加对象
List<User> userList = new ArrayList<User>();
User user1 = new User("张三", "男", "18");
User user2 = new User("李四", "男", "19");
User user3 = new User("王五", "男", "20");
userList.add(user1);
userList.add(user2);
userList.add(user3);
PrintWriter out = response.getWriter();
String str = null;
try {
//帐号密码如果匹配则把list 返回给界面
if (request.getParameter("userName").equals("jquery")
&& request.getParameter("password").equals("ajax")) {
str = JSONObject.quote(JSONUtil.toJSONString(userList));
}
out.print(str);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("str "+str);
out.flush();
out.close();
}
}
Html代码
<body>
帐号jquery 密码ajax
<form id="mainform">
<ul>
<li>
帐号
<input type="text" name="userName" />
</li>
<li>
密码
<input type="password" name="password" />
</li>
<li>
<input onclick="login()" type="button" value="登录" />
</li>
</ul>
</form>
查询到的数据
<div id="diva">
</div>
<script type="text/javascript">
function login(){
//获取form的参数
var args =$("#mainform").serialize();
//调用jquery 的json获取方法
//三个参数分别为 ：请求路径 ，请求参数，返回数据的回调函数
$.getJSON("servlet/UserServlet",args,function (data){
if(data!=null){
补充：web前端 , JavaScript ,
