求助大神：如何从电脑上随机输入限定范围的数字
这道题是井字游戏。3*3的格，人和电脑玩，如果谁的棋子连在一起是三个，谁就胜出。这段代码是两人玩的，一个人用“X”， 另一个用“O”， “X”顺序先于“O”。
想把这段代码改成人和电脑一起玩，人放入棋子后，电脑随机放入一个棋子。不需要用博弈算法。
大概知道使用random实现，求助各位大神，如何实现这个游戏。
如果各位大神有更好的方法，也可以贴出来，一起分享。
谢过了
import java.util.Scanner;--------------------编程问答-------------------- 如果不用博弈算法。那就很简单的。
/**
* Tic-Tac-Toe: Two-player console, non-graphics, non-OO version.
* All variables/methods are declared as static (belong to the class)
* in the non-OO version.
*/
public class Tic {
// Name-constants to represent the seeds and cell contents
public static final int EMPTY = 0;
public static final int CROSS = 1;
public static final int NOUGHT = 2;
// Name-constants to represent the various states of the game
public static final int PLAYING = 0;
public static final int DRAW = 1;
public static final int CROSS_WON = 2;
public static final int NOUGHT_WON = 3;
// The game board and the game status
public static final int ROWS = 3, COLS = 3; // number of rows and columns
public static int[][] board = new int[ROWS][COLS]; // game board in 2D array
// containing (EMPTY, CROSS, NOUGHT)
public static int currentState; // the current state of the game
// (PLAYING, DRAW, CROSS_WON, NOUGHT_WON)
public static int currentPlayer; // the current player (CROSS or NOUGHT)
public static int currntRow, currentCol; // current seed's row and column
public static Scanner in = new Scanner(System.in); // the input Scanner
/** The entry main method (the program starts here) */
public static void main(String[] args) {
// Initialize the game-board and current status
initGame();
// Play the game once
do {
playerMove(currentPlayer); // update currentRow and currentCol
updateGame(currentPlayer, currntRow, currentCol); // update currentState
printBoard();
// Print message if game-over
if (currentState == CROSS_WON) {
System.out.println("'X' won! Bye!");
} else if (currentState == NOUGHT_WON) {
System.out.println("'O' won! Bye!");
} else if (currentState == DRAW) {
System.out.println("It's a Draw! Bye!");
}
// Switch player
currentPlayer = (currentPlayer == CROSS) ? NOUGHT : CROSS;
} while (currentState == PLAYING); // repeat if not game-over
}
/** Initialize the game-board contents and the current states */
public static void initGame() {
for (int row = 0; row < ROWS; ++row) {
for (int col = 0; col < COLS; ++col) {
board[row][col] = EMPTY; // all cells empty
}
}
currentState = PLAYING; // ready to play
currentPlayer = CROSS; // cross plays first
}
/** Player with the "theSeed" makes one move, with input validation.
Update global variables "currentRow" and "currentCol". */
public static void playerMove(int theSeed) {
boolean validInput = false; // for input validation
do {
if (theSeed == CROSS) {
System.out.print("Player 'X', enter your move (row[1-3] column[1-3]): ");
} else {
System.out.print("Player 'O', enter your move (row[1-3] column[1-3]): ");
}
int row = in.nextInt() - 1; // array index starts at 0 instead of 1
int col = in.nextInt() - 1;
if (row >= 0 && row < ROWS && col >= 0 && col < COLS && board[row][col] == EMPTY) {
currntRow = row;
currentCol = col;
board[currntRow][currentCol] = theSeed; // update game-board content
validInput = true; // input okay, exit loop
} else {
System.out.println("This move at (" + (row + 1) + "," + (col + 1)
+ ") is not valid. Try again...");
}
} while (!validInput); // repeat until input is valid
}
/** Update the "currentState" after the player with "theSeed" has placed on
(currentRow, currentCol). */
public static void updateGame(int theSeed, int currentRow, int currentCol) {
if (hasWon(theSeed, currentRow, currentCol)) { // check if winning move
currentState = (theSeed == CROSS) ? CROSS_WON : NOUGHT_WON;
} else if (isDraw()) { // check for draw
currentState = DRAW;
}
// Otherwise, no change to currentState (still PLAYING).
}
/** Return true if it is a draw (no more empty cell) */
// TODO: Shall declare draw if no player can "possibly" win
public static boolean isDraw() {
for (int row = 0; row < ROWS; ++row) {
for (int col = 0; col < COLS; ++col) {
if (board[row][col] == EMPTY) {
return false; // an empty cell found, not draw, exit
}
}
}
return true; // no empty cell, it's a draw
}
/** Return true if the player with "theSeed" has won after placing at
(currentRow, currentCol) */
public static boolean hasWon(int theSeed, int currentRow, int currentCol) {
return (board[currentRow][0] == theSeed // 3-in-the-row
&& board[currentRow][1] == theSeed
&& board[currentRow][2] == theSeed
|| board[0][currentCol] == theSeed // 3-in-the-column
&& board[1][currentCol] == theSeed
&& board[2][currentCol] == theSeed
|| currentRow == currentCol // 3-in-the-diagonal
&& board[0][0] == theSeed
&& board[1][1] == theSeed
&& board[2][2] == theSeed
|| currentRow + currentCol == 2 // 3-in-the-opposite-diagonal
&& board[0][2] == theSeed
&& board[1][1] == theSeed
&& board[2][0] == theSeed);
}
/** Print the game board */
public static void printBoard() {
for (int row = 0; row < ROWS; ++row) {
for (int col = 0; col < COLS; ++col) {
printCell(board[row][col]); // print each of the cells
if (col != COLS - 1) {
System.out.print("|"); // print vertical partition
}
}
System.out.println();
if (row != ROWS - 1) {
System.out.println("-----------"); // print horizontal partition
}
}
System.out.println();
}
/** Print a cell with the specified "content" */
public static void printCell(int content) {
switch (content) {
case EMPTY: System.out.print(" "); break;
case NOUGHT: System.out.print(" O "); break;
case CROSS: System.out.print(" X "); break;
}
}
}
9个格子的label对象放到set中，每次从set中取出一个，画上x或O，可以用个标示符。每次判断每条线的情况。
这个线的情况也就6种。
思路就这样 --------------------编程问答--------------------
那请问电脑随机输入，这个怎么实现啊~谢啦 --------------------编程问答-------------------- 在 playerMove方法中
在输入一下这两个参数前先判断，如果是人 则输入 ，
int row = in.nextInt() - 1; // array index starts at 0 instead of 1
int col = in.nextInt() - 1;
机器则 随机生成两个数
Random rand = new Random();
int i = rand.nextInt(); //int范围类的随机数
i = rand.nextInt(100); //生成0-100以内的随机数
范围你自己按需设置
int row =i1
int col =i2 --------------------编程问答--------------------
在人点击一个格子的时候，点击事件最后从set里取一个（这个就是电脑的输入）绘图 --------------------编程问答--------------------
好的，我清楚了。谢谢了。
还有就是这段代码属于OOP design吗？
我觉得不是，怎么才能用OO design去实现啊？ 谢啦，版主~ --------------------编程问答-------------------- 这个纯属是面向过程的，如果需要写成OO的，首先是要把问题抽象出来
就这个问题，可以抽象出三个对象，棋盘、以及两个Player，棋盘负责显示棋盘和棋子，Player负责从棋盘获取数据，然后下棋
main函数属于程序入口，通过main函数将三个对象连接起来 --------------------编程问答--------------------
嗯哪，我知道了。
我有个不情之请，你能不能帮我大概的实现一下啊， 如果你有时间的话。先谢过了。 --------------------编程问答--------------------
因为我OO 不是很熟悉，一直在学习。但是有个面试又是要求写成OO， 能不能向你学习一下怎么实现它？谢谢
补充：Java , Java SE
