AES加密解密算法的Java实现
工作需要，花了两个下午将Aes算法了解了一下并用java实现了一遍（此处借鉴了老外的C#的实现），本人非信息安全专业和软件，代码还有漏洞，欢迎指出~~~
先贴上代码：
=================================================AES.java主要的类实现====================================================
package aesHelper.Aes;
/**
* AES字节数组加密算法类
*
* @author DC 2011/11/5
*/
public class Aes
{
/*************************** 成员变量************************************/
private int Nb;// 以32位为单位的字长
private int Nk;// 以32位为单位的密钥长度
private int Nr;// 轮数
private byte[] key;// 密钥
private byte[][] Sbox;// S盒矩阵
private byte[][] iSbox;// s盒逆矩阵
private byte[][] w;// 密钥调度表
private byte[][] Rcon;// 轮常数表
private byte[][] State;// 状态矩阵
/**
* 构造方法
*
* @param keySize
* @param keyBytes
*/
public Aes(int keySize, byte[] keyBytes, int Nb)
{
SetNbNkNr(keySize, Nb);
this.key = new byte[this.Nk * 4];
this.key = keyBytes;
BuildSbox();
BuildInvSbox();
BuildRcon();
KeyExpansion();
}
/*************************** 私有方法************************************/
/**
* 生成Rcon轮常数矩阵
*/
private void BuildRcon()
{
// 0x00,0x01,0x02,0x04,
// 0x08,0x10,0x20,0x40,
// 0x80,0x1b,0x36,0x6c,
// 0xd8,0xab,0x4d,0x9a,
// 0x2f,0x5e,0xbc,0x63,
// 0xc6,0x97,0x35,0x6a,
// 0xd4,0xb3,0x7d,0xfa,
// 0xef,0xc5,0x91,0x39};
this.Rcon = new byte[100][4];
Rcon[0][0]=0x00;//Rcon[1][0]=0x01;
for(int i=1;i<100;i++)
{
Rcon[i][0]=gfmultby02(Rcon[i-1][0]);
}
}
/**
* 设置Nb,Nk,Nr
*
* @param keysize
*/
private void SetNbNkNr(int keysize, int Nb)
{
this.Nb = Nb;
switch (keysize)
{
case KEYSIZE.Bit128:
this.Nk = 4;
this.Nr = 10;
break;
case KEYSIZE.Bit192:
this.Nk = 6;
this.Nr = 12;
break;
case KEYSIZE.Bit256:
this.Nk = 8;
this.Nr = 14;
break;
}
}
/**
* 生成S盒矩阵
*/
private void BuildSbox()
{
this.Sbox = new byte[][] {
/* 0 1 2 3 4 5 6 7 8 9 a b c d e f */
/* 0 */{ 0x63, 0x7c, 0x77, 0x7b, (byte) 0xf2, 0x6b, 0x6f,
(byte) 0xc5, 0x30, 0x01, 0x67, 0x2b, (byte) 0xfe,
(byte) 0xd7, (byte) 0xab, 0x76 },
/* 1 */{ (byte) 0xca, (byte) 0x82, (byte) 0xc9, 0x7d,
(byte) 0xfa, 0x59, 0x47, (byte) 0xf0, (byte) 0xad,
(byte) 0xd4, (byte) 0xa2, (byte) 0xaf, (byte) 0x9c,
(byte) 0xa4, 0x72, (byte) 0xc0 },
/* 2 */{ (byte) 0xb7, (byte) 0xfd, (byte) 0x93, 0x26, 0x36,
0x3f, (byte) 0xf7, (byte) 0xcc, 0x34, (byte) 0xa5,
(byte) 0xe5, (byte) 0xf1, 0x71, (byte) 0xd8, 0x31, 0x15 },
&nbs
补充：综合编程 , 安全编程 ,
