Common Lisp --- 计算 3x+1 问题
print?
[ruby]
(defun x-test (x)
(when (not (= x 1))
(cond
((= 1 (mod x 2))
(format t "3*~d+1=~d~%" x (+ 1 (* 3 x)))
(x-test (+ 1 (* 3 x))))
((= 0 (mod x 2))
(format t "~d/2=~d~%" x (/ x 2))
(x-test (/ x 2))))))
(defun x-test (x)
(when (not (= x 1))
(cond
((= 1 (mod x 2))
(format t "3*~d+1=~d~%" x (+ 1 (* 3 x)))
(x-test (+ 1 (* 3 x))))
((= 0 (mod x 2))
(format t "~d/2=~d~%" x (/ x 2))
(x-test (/ x 2))))))运行结果:
补充：综合编程 , 其他综合 ,
