c语言编程 万年历查询系统

基本要求：
1．  查询某年某月某日（阳历）是星期几；
2．  判断某年是否是闰年；
3．  查询某月的最大天数；
4．  打印某年的全年日历或某年某月的月历。
5．  系统完成后应实现类似下图所示界面。
 

追问：您好，我放到VC里试了一下，有62个错误。

答案：按你的要求写的 如果不能正常运行联系我

#include <stdio.h>
#include <stdlib.h>
bool isLeapyear( int nowYear );
int calcuWeek( int totalDays );
int calcuDays( int nowYear,int nowMonth,int nowDay );
bool checkValid( int nowYear,int nowMonth,int nowDay );
void nowMonthprint( int nowYear,int nowMonth,int nowDay );
void weekDayPrint( int nowYear,int nowMonth,int nowDay );
void nowYearprint( int nowYear );
void menuPrint();
const int leapDay[12]={31,29,31,30,31,30,31,31,30,31,30,31};//存储闰年每月天数
const int noleapDay[12]={31,28,31,30,31,30,31,31,30,31,30,31};//存储非闰年每月天数
int main()
{
 int year,month,day;
 while( true )
 {
  menuPrint();
  int op;
  scanf("%d",&op);
  switch( op )
  {
   case 1:
   {
    printf("请输入年月日（格式为YYYY-MM-DD）：");
    scanf("%d-%d-%d",&year,&month,&day);
    if ( checkValid(year,month,day) )
     weekDayPrint(year,month,day);
    else
    {
     printf("输入错误!!!退出操作\n");
     break;
    }
    break;
   }
   case 2:
   {
    printf("请输入需要查询的年份：");
    scanf("%d",&year);
    if( year > 9999 || year < 0 )
    {
     printf("年份输入错误!!!退出操作\n\n");
     break;
    }
    if ( isLeapyear( year ) )
     printf("%-4d年是闰年！！！\n\n",year);
    else
     printf("%-4d年是平年！！！\n\n",year);
    break;
   }
   case 3:
    printf("请输入需要查询的年份：");
    scanf("%d",&year);
    if( year > 9999 || year < 0 )
    {
     printf("年份输入错误!!!退出操作\n\n");
     break;
    }
    nowYearprint(year);
    break;
   case 4:
    printf("请输入年月日（格式为YYYY-MM-DD）：");
    scanf("%d-%d-%d",&year,&month,&day);
    if ( checkValid(year,month,day) )
     nowMonthprint(year,month,day);
    else
    {
     printf("输入错误!!!退出操作\n");
     break;
    }
    break;
   case 5:
    int maxdays;
    printf("请输入需要查询的年份及月份（格式YYYY-MM）：");
    scanf("%d-%d",&year,&month);
    if( year > 9999 || year < 0 || month > 12 || month < 0 )
    {
     printf("年份及月份输入错误!!!退出操作\n\n");
     break;
    }
    if ( isLeapyear(year))
     maxdays = leapDay[month-1];
    else
     maxdays = noleapDay[month-1];
    printf("%d年%d月最大天数为%d\n\n",year,month,maxdays);
    break;
   case 6:
    printf("退出系统，谢谢使用\n\n");
    return 0;
    break;
  }
 }
    return 0;
}
bool isLeapyear( int nowYear ) // 判断是否闰年
{
    if( nowYear%4 == 0 && nowYear%100 != 0 || nowYear%400 == 0)
        return true;
    else
        return false;
}
bool checkValid( int nowYear,int nowMonth,int nowDay )// 输入合法性检查
{
    if ( nowYear <= 0 )
    {
        printf( "输入年份不合法！！！");
        return false;
    }
    if ( nowMonth < 0 && nowMonth > 12 )
    {
        printf("输入月份不合法！！！");
        return false;
    }
    if ( nowDay < 0 && nowDay > 31 && isLeapyear(nowYear) )
    {
        printf("输入号数不合法！！！");
        return false;
    }
    if ( nowDay < 0 && nowDay > 30 && !isLeapyear(nowYear) )
    {
        printf("输入号数不合法！！！");
        return false;
    }
    return true;
}
int calcuDays( int nowYear,int nowMonth,int nowDay )// 计算总天数
{
    int days = 0;
 int mon = 0;
    for ( int i = 1;i < nowYear;i++ )
    {
        if( isLeapyear( i ) )
            days += 366;
        else
            days += 365;
    }
    for ( int j = 1;j < nowMonth;j++ )
    {
        if ( isLeapyear(nowYear) )
   mon = mon + leapDay[j-1];
  else
   mon = mon + noleapDay[j-1];
    }
    days  = days + mon + nowDay;
    return days;
}
int calcuWeek( int totalDays ) // 计算星期几
{
    int weekNo = totalDays%7;
    return weekNo;
}
void weekDayPrint( int nowYear,int nowMonth,int nowDay ) //打印某年某日星期几
{
 int days = calcuDays(nowYear,nowMonth,nowDay);
 int weekNo = calcuWeek( days );
 switch ( weekNo )
 {
  case 0:
   printf( "%-4d年%-2d月%-2d日是星期天！！！",nowYear,nowMonth,nowDay);
   break;
  case 1:
   printf( "%-4d年%-2d月%-2d日是星期一！！！",nowYear,nowMonth,nowDay);
   break;
  case 2:
   printf( "%-4d年%-2d月%-2d日是星期二！！！",nowYear,nowMonth,nowDay);
   break;
  case 3:
   printf( "%-4d年%-2d月%-2d日是星期三！！！",nowYear,nowMonth,nowDay);
   break;
  case 4:
   printf( "%-4d年%-2d月%-2d日是星期四！！！",nowYear,nowMonth,nowDay);
   break;
  case 5:
   printf( "%-4d年%-2d月%-2d日是星期五！！！",nowYear,nowMonth,nowDay);
   break;
  case 6:
   printf( "%-4d年%-2d月%-2d日是星期六！！！",nowYear,nowMonth,nowDay);
   break;
 }
 printf("\n\n");
}
void nowMonthprint( int nowYear,int nowMon

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