困扰许久的jsp表单提交路径问题，请各位大神们帮忙解决啊
前台login.jsp:<form action="/servlet/NewCheck" method="post">
<table align="center">
<tr>
<td class="logintd1">用户名：</td>
<td><input type="text" name="username"id="username" size="18"onblur="checkname();"/><label class="red" id="divusername"></label> </td>
</tr>
<tr>
<td>密码：</td>
<td> <input type="password" id="password1" size="18" onblur="checkpwd();"/> <label class="red" id="divpassword1"></label></td>
</tr>
<tr>
<td> <input type="submit" value="登录"/></td>
<td><a href="#">忘记密码？</a></td>
</tr>
<tr>
<td colspan="2"><a href="index.jsp">返回主页</a> | <a href="register.jsp">快速注册</a></td>
</tr>
</table>
</form>
servlet代码：
NewCheck.java
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
public class NewCheck extends HttpServlet {
public void destroy() {
super.destroy(); // Just puts "destroy" string in log
// Put your code here
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
String username=request.getParameter("username");
HttpSession session=request.getSession();
String temp=session.getAttribute("logined").toString();
if(temp.equals("username"))
{
session.setAttribute("logined", "username");
RequestDispatcher view=request.getRequestDispatcher("index.jsp");
view.forward(request,response);
}
else
{
session.setAttribute("logined", "username");
RequestDispatcher view=request.getRequestDispatcher("login.jsp");
view.forward(request,response);
}
out.flush();
out.close();
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doPost(request,response);
}
public void init() throws ServletException {
// Put your code here
}
}
web.xml配置：
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>NewCheck</servlet-name>
<servlet-class>NewCheck</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>NewCheck</servlet-name>
<url-pattern>/servlet/NewCheck</url-pattern>
</servlet-mapping>
tomcat 6.0运行结果提示：
type Status report
message /servlet/NewCheck
description The requested resource (/servlet/NewCheck) is not available.
希望大家帮帮忙啊 JSP jsp表单提交，404错误 Servlet --------------------编程问答--------------------
项目路径：--------------------编程问答--------------------
这样action="MyBBS/servlet/NewCheck"
或者在jsp页面上加红色部分
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>"> <title>My JSP 'index.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<script type="text/javascript" src="js/function.js"></script>
</head>
先这样试试，看看行不行 --------------------编程问答-------------------- jsp页面加这个
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<base href="<%=basePath%>"> --------------------编程问答--------------------
还是The requested resource (/MyBBS/servlet/NewCheck) is not available.--------------------编程问答-------------------- <servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>NewCheck</servlet-name>
<servlet-class>MyBBS.NewCheck</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>NewCheck</servlet-name>
<url-pattern>/NewCheck</url-pattern>
</servlet-mapping> --------------------编程问答-------------------- web.xml里面servlet的路径不对 --------------------编程问答-------------------- 现在我把web.xml改为：
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>NewCheck</servlet-name>
<servlet-class>NewCheck</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>NewCheck</servlet-name>
<url-pattern>/NewCheck</url-pattern>
</servlet-mapping>
表单提交改为了：
<form action="NewCheck" method="get">
之后在myeclipse 8.5里运行能成功，可是关了myeclipse的内部服务器而去运行外部Tomcat/6.0.16时，出现404错误：还是提示The requested resource (/MyBBS/NewCheck) is not available。
是我的tomcat配置错了吗？各位大神啊，快出来吧······ --------------------编程问答--------------------
404看看tomcat6.0运行的时候是不是报错了
补充：Java , Web 开发
