当前位置:编程学习 > C#/ASP.NET >>

求一段广东省的gps导航数据

开发gps还真的很不方便啊
调试就是一个很大很大的问题
公司里面用gps接收器一颗卫星都接收不了
好像只有抱着个笔记本跑马路上调试了
可是这实在有点傻
所以在这里特求一段广东省gps有效的导航数据测试程序
格式大约:
$GPRMC,<1>,<2>,<3>,<4>,<5>,<6>,<7>,<8>,<9>,<10>,<11>,<12>*hh 

<1> UTC时间,hhmmss(时分秒)格式 
<2> 定位状态,A=有效定位,V=无效定位 
<3> 纬度ddmm.mmmm(度分)格式(前面的0也将被传输) 
<4> 纬度半球N(北半球)或S(南半球) 
<5> 经度dddmm.mmmm(度分)格式(前面的0也将被传输) 
<6> 经度半球E(东经)或W(西经) 
<7> 地面速率(000.0~999.9节,前面的0也将被传输) 
<8> 地面航向(000.0~359.9度,以真北为参考基准,前面的0也将被传输) 
<9> UTC日期,ddmmyy(日月年)格式 
<10> 磁偏角(000.0~180.0度,前面的0也将被传输) 
<11> 磁偏角方向,E(东)或W(西) 
<12> 模式指示(仅NMEA0183 3.00版本输出,A=自主定位,D=差分,E=估算,N=数据无效)

我在公司里用接收器接收到无效的数据摘取部分:
$GPGGA,080509.351,2308.1551,N,11318.0940,E,0,00,,1.4,M,-6.6,M,,0000*66
$GPRMC,080509.351,V,2308.1551,N,11318.0940,E,,,210809,,,N*79
$GPVTG,,T,,M,,N,,K,N*2C
$GPGGA,080510.343,2308.1551,N,11318.0940,E,0,00,,1.4,M,-6.6,M,,0000*6D
$GPRMC,080510.343,V,2308.1551,N,11318.0940,E,,,210809,,,N*72
$GPVTG,,T,,M,,N,,K,N*2C
$GPGGA,080511.343,2308.1551,N,11318.0940,E,0,00,,1.4,M,-6.6,M,,0000*6C
$GPRMC,080511.343,V,2308.1551,N,11318.0940,E,,,210809,,,N*73
$GPVTG,,T,,M,,N,,K,N*2C
$GPGGA,080512.351,2308.1551,N,11318.0940,E,0,00,,1.4,M,-6.6,M,,0000*6C
$GPGSA,A,1,,,,,,,,,,,,,,,*1E
$GPGSV,3,1,12,25,79,219,,07,69,309,,11,63,175,,19,44,026,*73
$GPGSV,3,2,12,08,29,323,,13,26,225,,03,22,044,,06,12,047,*7C
$GPGSV,3,3,12,23,10,188,,28,10,300,,17,05,240,,16,04,095,*79
$GPRMC,080512.351,V,2308.1551,N,11318.0940,E,,,210809,,,N*73
--------------------编程问答-------------------- up! --------------------编程问答-------------------- Google Earth
补充:.NET技术 ,  C#
CopyRight © 2012 站长网 编程知识问答 www.zzzyk.com All Rights Reserved
部份技术文章来自网络,