android新手
做了个web服务端，如何用android客户端交互数据 --------------------编程问答-------------------- 使用json吧 --------------------编程问答-------------------- public static String doPostJson(String urlStr, Map<String, String> heads, String jsonStr){
try{
URL url = new URL(urlStr);
HttpURLConnection connection = ((HttpURLConnection) url.openConnection());
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
connection.setConnectTimeout(5000);
connection.setRequestMethod("POST");
connection.setRequestProperty("Charset", "UTF-8");
//connection.setRequestProperty("Content-Type", "application/json-rpc");
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
if (heads != null){
for(Map.Entry<String, String> head : heads.entrySet()){
connection.setRequestProperty(head.getKey(), head.getValue());
}
}
byte[] sendData = jsonStr.getBytes("UTF-8");
connection.setFixedLengthStreamingMode(sendData.length);
connection.connect();
OutputStream out = connection.getOutputStream();
//out.write(sendData, 0, sendData.length);
out.write(sendData);
out.flush();
out.close();
InputStream input = connection.getInputStream();
StringBuffer sb = new StringBuffer();
byte[] buffer = new byte[512];
int len;
while ((len = input.read(buffer)) != -1) {
sb.append(new String(buffer, 0, len));
}
input.close();
connection.disconnect();
return sb.toString();
}catch(Exception e){
Log.e("System.out", Log.getStackTraceString(e));
}
return "";
}
/**
* 执行一个Http Get 请求，返回请求响应的HTML
* @param url
* 请求的URL地址
* @param heads
* 请求时要设置的http头信息，没有设为null
* */
public static String doGet(String url, Map<String, String> heads)
{
HttpResponse httpResponse = null;
try
{
// 第1步：创建HttpGet对象
HttpGet httpGet = new HttpGet(url);
if (heads != null){
for(Map.Entry<String, String> head : heads.entrySet()){
httpGet.addHeader(head.getKey(), head.getValue());
}
}
// 第2步：使用execute方法发送HTTP POST请求，并返回HttpResponse对象
httpResponse = new DefaultHttpClient().execute(httpGet);
int statusCode = httpResponse.getStatusLine().getStatusCode();
if (statusCode == 200)
{
// 第3步：使用getEntity方法获得返回结果
String result = EntityUtils.toString(httpResponse.getEntity());
//System.out.println(result);
return result;
}
}
catch (Exception e)
{
Log.e("System.out", "Exception: "+Log.getStackTraceString(e));
}
return null;
}
--------------------编程问答-------------------- http://hi.baidu.com/yezhonglu/item/ad7b6aa6b1cb021a030a4d37
楼主可以参考一下 --------------------编程问答-------------------- 楼主可以参考一下 --------------------编程问答--------------------
这个还可以！可以试试
补充：移动开发 , Android
