谁知道为什么mLinearLayout2部分显示不出来?谢谢.

public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);

this.setTitle("却换图层");

mTextView1 = new TextView(this);
mTextView1.setText("图层名");

mMap = new HashMap<String, String>();
mMap.put("K1fdwe", "K1fdwe");
mMap.put("K2fdme", "K1fdwe");
mMap.put("K3fmfd", "K1fdwe");
mMap.put("K4fd", "K1fdwe");

for (Map.Entry<String, String> entry : mMap.entrySet()) {
String key = entry.getKey();
String value = entry.getValue();

mKeyList.add(key);
mValueList.add(value);
}

mListView1 = new ListView(this);
mListView1.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE);
mListView1.setOnItemClickListener(mOnItemClickListener);
ArrayAdapter<String> mAdapter1 = new ArrayAdapter<String>(this,
android.R.layout.simple_list_item_multiple_choice, mKeyList);//mKeyList有值
mListView1.setAdapter(mAdapter1);

mLinearLayout1 = new LinearLayout(this);
mLinearLayout1.setOrientation(LinearLayout.VERTICAL);
mLinearLayout1.addView(mTextView1, new LayoutParams(WC, WC));
mLinearLayout1.addView(mListView1, new LayoutParams(WC, WC));

mTextView2 = new TextView(this);
mTextView2.setText("图层描述");

mListView2 = new ListView(this);
ArrayAdapter<String> mAdapter2 = new ArrayAdapter<String>(this,
android.R.layout.simple_list_item_1, mValueList);//mValueList有值
mListView2.setAdapter(mAdapter2);

mLinearLayout2 = new LinearLayout(this);
mLinearLayout2.setOrientation(LinearLayout.VERTICAL);
mLinearLayout2.addView(mTextView2, new LayoutParams(WC, WC));
mLinearLayout2.addView(mListView2, new LayoutParams(WC, WC));

mLinearLayout3 = new LinearLayout(this);
mLinearLayout3.setOrientation(LinearLayout.HORIZONTAL);
mLinearLayout3.addView(mLinearLayout1, new LayoutParams(WC, FP));
mLinearLayout3.addView(mLinearLayout2, new LayoutParams(WC, FP));

this.setContentView(mLinearLayout3);
} --------------------编程问答-------------------- 建议用sdk中tools目录下的hierarchyviewer.bat工具查看下布局，个人感觉是mLinearLayout2被挤出到可视区域以外了。

补充：移动开发 ,  Android