经典union的使用

一个用户下广告位某一天有收入和支出有支出不一定有收入有收入不一定有支出下例为按用户查询 sanhao 下的信息
支出如下：

收入如下：

按天进行查询，例如查询：

得到结果如下：

使用一般的按日期左关联，会出现错误。

正确的使用如下，把每个表的收入或者支出补全为0，然后union合并再进行分组合并

  select rownum rn,mm0.accesstime,nvl(mm1.inall,0) inall
  ,nvl(mm1.outall,0) outall,mm1.placeid
  ,decode(mm1.inall,null,0,mm1.inall)-decode(mm1.outall,null,0,mm1.outall) profit
  ,decode(inall,0,'-', to_char(round((decode(mm1.inall,null,0,mm1.inall)-decode(mm1.outall,null,0,mm1.outall) )/inall,4)*100)||'%') proRate
 
  from
  (
  select column_value as accesstime from table(fn_split('2013-10-12,2013-10-13,2013-10-14',',') )
  ) mm0,
  ( 
  select accesstime,placeid,sum(inall) inall,sum(outall2) outall  from
  ( 
  --包广告位付款
  select 0 inall,to_char(rd.accounttime,'yyyy-mm-dd') as accesstime,rd.placeid ,decode(sum(rd.paysum),null,0,sum(rd.paysum)) outall2
  from ad_paidrecord rd 
  inner join ad_place pl on rd.placeid=pl.placeid and pl.ismonthly=1
  where rd.placeid!=0--包广告位
  and pl.ismonthly=1
  and rd.rectype in(0,2)
  and rd.accounttime>= to_date('2013-10-12','yyyy-mm-dd')
  and rd.accounttime<= to_date('2013-10-14','yyyy-mm-dd')--根据记账日期（小的日期）
  --and (i_placeid=-1 or rd.placeid=i_placeid)
  and (rd.webuserid='sanhao' )
  group by rd.accounttime,rd.placeid
  union
  --总收入 
  select sum(v.income)inall,to_char(v.accesstime,'yyyy-mm-dd') as accesstime,v.placeid,0
  from v_placeincome v
  where v.accesstime >= to_date('2013-10-12','yyyy-mm-dd')
  and v.accesstime <=  to_date('2013-10-14','yyyy-mm-dd')
  --  and (i_placeid=-1 or v.placeid=i_placeid)
  and v.ismonthly=1
  and (v.webuserid='sanhao')
  group by accesstime,placeid
  )
  group by accesstime,placeid
  )  mm1 
  where  mm0.accesstime=mm1.accesstime(+)
  and (inall>0 or (nvl(mm1.outall,0))>0)
  order by placeid,mm0.accesstime asc;