九度OJ 1089 数字反转

题目分析：

使用队列存放每一位的数字，然后输出并计算得到反转数值，从而实现数字反转。

源代码：

[cpp]
#include<iostream>
#include<queue>
using namespace std;

int main()
{
    int n;
    cin>>n;
    int m = 1;
    while (m <= n)   //控制行数循环
    {
        int a,b;
        cin>>a>>b;
        int sum = 0,temp = 0;
        queue<int> a1,b1,sum1;
        sum = a + b;
        temp = sum;
        while (sum > 0)
        {
            sum1.push(sum % 10);
            sum = sum / 10;
        }
        while (a > 0)    //将a中每个数字入队列
        {
            a1.push(a % 10);
            a = a / 10;
        }
        while (b > 0)    //将b中每个数字入队列
        {
            b1.push(b % 10);
            b = b / 10;
        }
        a = 0, b =0, sum = 0;
        for (int k = 0; k < sum1.size(); k++)
        {
            sum = sum * 10 + sum1.front();
            sum1.pop();
        }
        for (int i = 0; i < a1.size(); i++)
        {
            a = a * 10 + a1.front();
            a1.pop();
        }
        for (int j = 0; j < b1.size(); j++)
        {
            b = b * 10 + b1.front();
            b1.pop();
        }
        if (sum == a + b)
        {
            cout<<temp<<endl;;
        }
        else
        {
            cout<<"NO"<<endl;
        }
        m ++;
    }
    return 0;
}

#include<iostream>
#include<queue>
using namespace std;

int main()
{
int n;
cin>>n;
int m = 1;
while (m <= n) //控制行数循环
{
  int a,b;
  cin>>a>>b;
  int sum = 0,temp = 0;
  queue<int> a1,b1,sum1;
  sum = a + b;
  temp = sum;
  while (sum > 0)
  {
   sum1.push(sum % 10);
   sum = sum / 10;
  }
  while (a > 0) //将a中每个数字入队列
  {
   a1.push(a % 10);
   a = a / 10;
  }
  while (b > 0) //将b中每个数字入队列
  {
   b1.push(b % 10);
   b = b / 10;
  }
  a = 0, b =0, sum = 0;
  for (int k = 0; k < sum1.size(); k++)
  {
   sum = sum * 10 + sum1.front();
   sum1.pop();
  }
  for (int i = 0; i < a1.size(); i++)
  {
   a = a * 10 + a1.front();
   a1.pop();
  }
  for (int j = 0; j < b1.size(); j++)
  {
   b = b * 10 + b1.front();
   b1.pop();
  }
  if (sum == a + b)
  {
   cout<<temp<<endl;;
  }
  else
  {
   cout<<"NO"<<endl;
  }
  m ++;
}
return 0;
}

补充：软件开发 , C++ ,