C++当多次调用同一实参的模板,到底编译器实列化几次份代码的问题
提问:
template <typename T> void fun(T num){};
如果调用
fun(double(1.23));
fun(int(1));
编译器会实列化fun(double num)和fun(int num)
但是我想问得是如果调用两次fun(int)
fun(int(1));
fun(int(2));
编译器会实列两个fun(int),还是一个啊????疑惑至极。
求好心人解答。
[cpp]
#include <iostream>
using namespace std;
template <typename T>
void fun(T num)
{
static int cnt = 0;
cnt++;
cout << "cnt = " << cnt << "\t" << "num = " << num << endl;
}
int main()
{
int a = 1;
fun(a);
int b = 2;
fun(b);
double c = 2.23;
fun(c);
return 0;
}
#include <iostream>
using namespace std;
template <typename T>
void fun(T num)
{
static int cnt = 0;
cnt++;
cout << "cnt = " << cnt << "\t" << "num = " << num << endl;
}
int main()
{
int a = 1;
fun(a);
int b = 2;
fun(b);
double c = 2.23;
fun(c);
return 0;
}
结果为:
cnt = 1 num = 1
cnt = 2 num = 2
cnt = 1 num = 2.23
结论:只有一次
补充:软件开发 , C++ ,