程序：#include <stdio.h>
void main ()
{
int muban[3][3]={{1,2,1},{2,4,2},{1,2,1}};
int i,j,ii,jj;
int sum1=0;
for (i=0;i<3;i++)
for (j=0;j<3;j++)
sum1+=muban[i][j];
printf ("sum is %f \n",sum1);
for (ii=0;ii<=2;ii++)
{ for ( jj=0;jj<=2;jj++)
{ printf(" %d ",muban[ii][jj]);
}
printf ("\n");
}
}答案：printf ("sum is %f \n",sum1);
//改为：%f改%d
printf ("sum is %d \n",sum1);其他：应该没错啊 #include <stdio.h>
void main ()
{
int muban[3][3]={{1,2,1},{2,4,2},{1,2,1}};
int i,j,ii,jj;
int sum1=0;
for (i=0;i<3;i++)
{ for (j=0;j<3;j++)
{
sum1+=muban[i][j];
}
//printf ("sum is %f \n",sum1);//你的输出类型弄错了，整数用%d
printf ("sum is %d \n",sum1);
}
for (ii=0;ii<=2;ii++)
{ for ( jj=0;jj<=2;jj++)
{ printf(" %d ",muban[ii][jj]);
}
printf ("\n");
}
} for (i=0;i<3;i++)
{ for (j=0;j<3;j++)
{
sum1+=muban[i][j];
}
}
要不试试看看 应该是printf ("sum is %f \n",sum1); 破坏了程序的完整性.导致程序出错
可以修改为printf ("sum is %f \n",(double)sum1);
或者printf ("sum is %d\n",(double)sum1); 数据类型你最好好好看一下，%d%f%s printf ("sum is %f \n",sum1);// 这是浮点型的
printf ("sum is %d \n",sum1);// 这是整型的上一个：郝斌C语言的课件发我一份吧，万分感谢! justemem@gmail.com
下一个：关于C语言的问题！~~求解！！！
