解决struts1中请求跳转到Action而非execute的问题

jsp 代码：

<html:form action="/loginAction.do" >

<input type="hidden" name="method" value="login" /> 

<html:hidden property="id" /> 

用户名:<html:text property="uname" /> <br>

密　码:<html:password property="upass" /><br>

<html:submit/>

</html:form>

 

struts-config.xml 代码:

<struts-config>

<form-beans>

<form-bean name="userInfo" type="UserInfo" />

</form-beans>

<action-mappings>

<action path="/loginAction" type="LoginAction" name="userInfo" scope="request" parameter="method">

<forward name="success" path="/success.jsp" />

<forward name="error" path="/error.jsp" />

</action>

</action-mappings>

</struts-config>

 

java 代码:

public class LoginAction extends DispatchAction

{

 

public ActionForward login(ActionMapping mapping, ActionForm form,

HttpServletRequest request, HttpServletResponse response)

throws Exception

{

UserInfo dform = (UserInfo) form;

String uname = dform.getUname();

String upass = dform.getUpass();

System.out.println(uname + " login " + upass);

return mapping.findForward("success");

}

 

@Override

public ActionForward execute(ActionMapping mapping, ActionForm form,

HttpServletRequest request, HttpServletResponse response)

throws Exception

{

UserInfo dform = (UserInfo) form;

String uname = dform.getUname();

String upass = dform.getUpass();

System.out.println(uname + " execute " + upass);

return mapping.findForward("success");

}

}

 

在网上查了一些相关的资料，得知是在struts-config.xml中添加parameter=”method”。

在页面添加<input type=”hidden” name=”method” value=”login” /> 就可以了！

补充：Web开发 , Jsp ,