好心人帮看一下，关于搜索传参的问题。

高手们，我用这种方法写搜索，好像传参不对，请帮我改正一下，谢谢谢谢谢谢谢谢谢谢谢谢谢谢！！！！

前台搜索框：
<form id="form1" name="form1" method="post" action="search.aspx">
  搜索：
  <input type="text" name="key" />
  <select name="t">
  <option value="1">新闻</option>
  <option value="2">产品</option>
  <option value="3">下载</option>
  </select>
  <input type="submit" name="Submit" value="search" />
  </form>

目标搜索结果显示页。
protected StringBuilder sb = new StringBuilder();
  protected void Page_Load(object sender, EventArgs e)
  {
  string t = Request.QueryString["t"];
  string key = Request.QueryString["key"];
  DataTable dt = new DataTable();

  if (t == null || t == "")
  {
  Response.Write("<script>alert('请选择要搜索的栏目!');history.back();</script>");
  if (t == "1")
  {
  dt = Class.gd("select * from [news] where title like '%" + key + "%' order by id desc").Tables[0];
  for (int i = 0; i < dt.Rows.Count; i++)
  {
  sb.Append(" <span>" + dt.Rows[i]["data"].ToString() + "</span><a href=\"news_view.asp?id=" + dt.Rows[i]["id"].ToString() + "\">=" + dt.Rows[i]["title"].ToString() + "</a> </li>");
  }
  }
  if (t == "2")
  {
  dt = Class.gd("select * from [product] where title like '%" + key + "%' order by id desc").Tables[0];
  for (int i = 0; i < dt.Rows.Count; i++)
  {
  sb.Append(" <span>" + dt.Rows[i]["data"].ToString() + "</span><a href=\"product_view.asp?id=" + dt.Rows[i]["id"].ToString() + "\">=" + dt.Rows[i]["title"].ToString() + "</a> </li>");
  }
  }

  else
  {
  dt = Class.gd("select * from [product] where title like '%" + key + "%' order by id desc").Tables[0];
  for (int i = 0; i < dt.Rows.Count; i++)
  {
  sb.Append(" <span>" + dt.Rows[i]["data"].ToString() + "</span><a href=\"download_view.asp.asp?id=" + dt.Rows[i]["id"].ToString() + "\">=" + dt.Rows[i]["title"].ToString() + "</a> </li>");
  }
  }
  } --------------------编程问答-------------------- string t = Request.Form["t"]; --------------------编程问答-------------------- try:
string t = Request["t"];
  string key = Request["key"];
--------------------编程问答-------------------- 你看下你参数获取没你传参的方式是为post 但是你获取参数的方式为get的方式那肯定获取不到撒  Request.Form["t"];这样获取下面的没看了看的头大！

补充：.NET技术 ,  ASP.NET