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rem 实现rsa加密与解密的vbs类文件
rem 文章标题:在asp中通过vbs类实现rsa加密与解密
rem 收集整理:yanek
rem 联系:aspboy@263.net
' RSA Encryption Class
'
' .PrivateKey
' Your personal private key. Keep this hidden.
'
' .PublicKey
' Key for others to encrypt data with.
'
' .Modulus
' Used with both public and private keys when encrypting
' and decrypting data.
'
' .GenKey()
' Creates Public/Private key set and Modulus
'
' .Crypt(pLngMessage, pLngKey)
' Encrypts/Decrypts message and returns
' as a string.
'
' .Encode(pStrMessage)
' Encrypts message and returns in double-hex format
'
' .Decode(pStrMessage)
' Decrypts message from double-hex format and returns a string
'
Class clsRSA
Public PrivateKey
Public PublicKey
Public Modulus
Public Sub GenKey()
Dim lLngPhi
Dim q
Dim p
Randomize
Do
Do
' 2 random primary numbers (0 to 1000)
Do
p = Rnd * 1000 \ 1
Loop While Not IsPrime(p)
Do
q = Rnd * 1000 \ 1
Loop While Not IsPrime(q)
' n = product of 2 primes
Modulus = p * q \ 1
' random decryptor (2 to n)
PrivateKey = Rnd * (Modulus - 2) \ 1 + 2
lLngPhi = (p - 1) * (q - 1) \ 1
PublicKey = Euler(lLngPhi, PrivateKey)
Loop While PublicKey = 0 Or PublicKey = 1
' Loop if we can't crypt/decrypt a byte
Loop While Not TestCrypt(255)
End Sub
Private Function TestCrypt(ByRef pBytData)
Dim lStrCrypted
lStrCrypted = Crypt(pBytData, PublicKey)
TestCrypt = Crypt(lStrCrypted, PrivateKey) = pBytData
End Function
Private Function Euler(ByRef pLngPHI, ByRef pLngKey)
Dim lLngR(3)
Dim lLngP(3)
Dim lLngQ(3)
Dim lLngCounter
Dim lLngResult
Euler = 0
lLngR(1) = pLngPHI: lLngR(0) = pLngKey
lLngP(1) = 0: lLngP(0) = 1
lLngQ(1) = 2: lLngQ(0) = 0
lLngCounter = -1
Do Until lLngR(0) = 0
lLngR(2) = lLngR(1): lLngR(1) = lLngR(0)
lLngP(2) = lLngP(1): lLngP(1) = lLngP(0)
lLngQ(2) = lLngQ(1): lLngQ(1) = lLngQ(0)
lLngCounter = lLngCounter + 1
lLngR(0) = lLngR(2) Mod lLngR(1)
lLngP(0) = ((lLngR(2)\lLngR(1)) * lLngP(1)) + lLngP(2)
lLngQ(0) = ((lLngR(2)\lLngR(1)) * lLngQ(1)) + lLngQ(2)
Loop
lLngResult = (pLngKey * lLngP(1)) - (pLngPHI * lLngQ(1))
If lLngResult > 0 Then
Euler = lLngP(1)
Else
Euler = Abs(lLngP(1)) + pLngPHI
End If
End Function
Public Function Crypt(pLngMessage, pLngKey)
On Error Resume Next
Dim lLngMod
Dim lLngResult
Dim lLngIndex
If pLngKey Mod 2 = 0 Then
lLngResult = 1
For lLngIndex = 1 To pLngKey / 2
lLngMod = (pLngMessage ^ 2) Mod Modulus
' Mod may error on key generation
lLngResult = (lLngMod * lLngResult) Mod Modulus
If Err Then Exit Function
Next
Else
lLngResult = pLngMessage
For lLngIndex = 1 To pLngKey / 2
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