PHP获取url的函数代码

答案：
复制代码 代码如下:
 
function geturl($url) 
{ 
$ch = curl_init(); 
$timeout = 5; 
curl_setopt($ch, CURLOPT_URL, $url); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); 
//在需要用户检测的网页里需要增加下面两行 
//curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_ANY); 
//curl_setopt($ch, CURLOPT_USERPWD, US_NAME.”:”.US_PWD); 
$contents = curl_exec($ch); 
curl_close($ch); 
$contents = str_replace("document.write('","",$contents); 
$contents = str_replace("');","",$contents); 
$contents = str_replace("\\n","",$contents); 
$contents = str_replace("\\","",$contents); 
echo $contents; 
} 

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