设置树节点的展开和折叠出现奇怪错误 JS脚本错误提示EVENT为空或不是对象
var objtree = document.getElementById("TreeView1");
var node = objtree.getChildren();
if(node.getAttribute("Expanded")==true)
{
node[0].setAttribute("Expanded", "true");
执行成功
}
else
{
node[0].setAttribute("Expanded", "true");
执行失败 JS脚本错误提示EVENT为空或不是对象
} --------------------编程问答-------------------- node[0].setAttribute("Expanded", "true");
这句换成node[0].Expanded="true";试下 --------------------编程问答-------------------- 试过了 不行还是一样的
--------------------编程问答-------------------- var objtree = document.getElementById("TreeView1");
var node = objtree.getChildren();
if(node.getAttribute("Expanded")==true)
{
node[0].setAttribute("Expanded", "true");
执行成功
}
else
{
node[0].setAttribute("Expanded", "true还是false");
执行失败 JS脚本错误提示EVENT为空或不是对象
} --------------------编程问答-------------------- 是True 这个时候node[0]的Expanded是false --------------------编程问答-------------------- 我是手动点击树节点折叠让它的Expanded为false 再执行展开时node[0].setAttribute("Expanded", "true"); JS脚本错误提示EVENT为空或不是对象
--------------------编程问答-------------------- 放完整的代码上来看看 --------------------编程问答-------------------- function findop(opflag ,pid, guid, company,sex)
{
var objtree = window.parent.document.getElementById("TreeView1");
var rootnode = objtree.getChildren();
//遍历树
findtree(objtree,rootnode[0],opflag,pid,guid, company,sex);
}
function findtree(objtree,node,opflag ,pid, guid, company,sex)
{
var ChildNode = node.getChildren();
var seximg="boy.gif";
if(sex==0)
seximg="girl.gif";
//没有子节点
if(ChildNode.length<1)
{
if(opflag=="ins")//公司档案开发时的特殊代码
{
if (node.getAttribute("NodeData").toUpperCase() == pid.toUpperCase())
{
//在当前查找到的节点下：添加子节点
var nodeadd = objtree.createTreeNode();
var parentNode = objtree.getTreeNode(objtree.clickedNodeIndex);
node.add(nodeadd);
nodeadd.setAttribute("Text", company);
nodeadd.setAttribute("NodeData", guid);
nodeadd.setAttribute("Target", "doss");
nodeadd.setAttribute("NavigateUrl","employee.aspx?pid="+pid);
nodeadd.setAttribute("ImageUrl","../../Images/"+seximg);
//parentNode.setAttribute("Expanded", "true");//展开父节点
// try
// {
node.setAttribute("Expanded", "true");//展开父节点
// //ExpandNode(node);
// var objtreeinnerHTML = window.parent.document.getElementById("TreeView1").innerHTML;
//
// window.parent.document.getElementById("TreeView1").innerHTML = objtreeinnerHTML.replace(""+company+"<tvns:treenode Expanded=\"Flase\"",""+company+"<tvns:treenode Expanded=\"True\"");
// }
// catch(ex)
// {
// alert(ex.description);
// }
return;
}
}
}
//存在子节点
for(var i=0;i<ChildNode.length;i++)
{
if(opflag=="ins")
{
if (node.getAttribute("NodeData").toUpperCase() == pid.toUpperCase())
{
//在当前查找到的节点下：添加子节点
var nodeadd = objtree.createTreeNode();
var parentNode = objtree.getTreeNode(objtree.clickedNodeIndex);
node.add(nodeadd);
nodeadd.setAttribute("Text", company);
nodeadd.setAttribute("NodeData", guid);
nodeadd.setAttribute("Target", "doss");
nodeadd.setAttribute("NavigateUrl","employee.aspx?pid="+pid);
nodeadd.setAttribute("ImageUrl","../../Images/"+seximg);
//parentNode.setAttribute("Expanded", "true");//展开父节点
try
{
if(node.getAttribute("Expanded"))
{
node.setAttribute("Expanded", "true");//展开父节点
}
else
{
//alert(parentNode.getAttribute("Text"));
//alert(node.getAttribute("Text"));
//node.setAttribute("Expanded", "true");//展开父节点
//var Expand=module_system_employee.Expanded_Node(node.getAttribute("NodeData"),true).value;
alert(parentNode.getAttribute("Expanded"));
parentNode.setAttribute("Expanded", "true");//展开父节点
}
}
catch(ex)
{
alert(ex.description);
}
return;
}
}
else if (ChildNode[i].getAttribute("NodeData").toUpperCase() == guid.toUpperCase())
{
if(opflag=="up")
{
ChildNode[i].setAttribute("Text", company);
ChildNode[i].setAttribute("ImageUrl","../../Images/"+seximg);
// try
// {
// ChildNode[i].setAttribute("Expanded", "true");//展开父节点
// }
// catch(ex)
// {
// alert(ex.description);
// }
}
else if(opflag=="del")
{
try
{
ChildNode[i].remove();
}
catch(ex)
{
//alert(ex.description);
}
}
return;
}
findtree(objtree,ChildNode[i],opflag ,pid, guid, company,sex);
}
} --------------------编程问答-------------------- 代码太多 要不远程调试一下 --------------------编程问答-------------------- 节点的数据都是数据库里的 --------------------编程问答-------------------- 1\findtree(objtree,rootnode[0],opflag,pid,guid, company,sex);
为什么提交了objtree还要提交rootnode[0]?
你这个递归本身的问题,写得太乱了
--------------------编程问答-------------------- function ExpandedAll(Node, Expanded) {
var ChildNode = Node.getChildren();
for (var i = 0; i < ChildNode.length; i++) {
ChildNode[0].getAttribute("Expanded", Expanded)
if (ChildNode[i].getChildren().length > 0) {
findtree(ChildNode[i], Expanded);
}
}
}
//展开
var objtree = window.parent.document.getElementById("TreeView1");
objtree.getAttribute("Expanded", true);
ExpandedAll(objtree, true);
//收缩
var objtree = window.parent.document.getElementById("TreeView1");
objtree.getAttribute("Expanded", false);
ExpandedAll(objtree, false); --------------------编程问答-------------------- 我调试了 展不开 当Expanded为false的时候 还是没反应
补充：.NET技术 , ASP.NET
