汇编代码 这个有办法突破20或者取消吗?
* Referenced by a CALL at Addresses:|:00C69B67 , :00C69B78 , :00C69B89 , :00C69B9A , :00C69BAB
|
:006BD18C 55 push ebp
:006BD18D 8BEC mov ebp, esp
:006BD18F 83C4F4 add esp, FFFFFFF4
:006BD192 53 push ebx
:006BD193 33DB xor ebx, ebx
:006BD195 895DF4 mov dword ptr [ebp-0C], ebx
:006BD198 894DF8 mov dword ptr [ebp-08], ecx
:006BD19B 8955FC mov dword ptr [ebp-04], edx
:006BD19E 8B45FC mov eax, dword ptr [ebp-04]
:006BD1A1 E84A85D4FF call 004056F0
:006BD1A6 8B45F8 mov eax, dword ptr [ebp-08]
:006BD1A9 E84285D4FF call 004056F0
:006BD1AE 33C0 xor eax, eax
:006BD1B0 55 push ebp
:006BD1B1 686CD26B00 push 006BD26C
:006BD1B6 64FF30 push dword ptr fs:[eax]
:006BD1B9 648920 mov dword ptr fs:[eax], esp
:006BD1BC 837DF800 cmp dword ptr [ebp-08], 00000000
:006BD1C0 7538 jne 006BD1FA
* Possible StringData Ref from Code Obj ->" Declare @Count integer Declare "
->"@I integer select @Count=Count(*) "
->"from "
|
:006BD1C2 6880D26B00 push 006BD280
:006BD1C7 FF75FC push [ebp-04]
* Possible StringData Ref from Code Obj ->" while @Count > 20 "
|
:006BD1CA 68D4D26B00 push 006BD2D4
* Possible StringData Ref from Code Obj ->" begin "
|
:006BD1CF 68F0D26B00 push 006BD2F0
* Possible StringData Ref from Code Obj ->" select @I = Max(ID) from "
|
:006BD1D4 6800D36B00 push 006BD300
:006BD1D9 FF75FC push [ebp-04]
* Possible StringData Ref from Code Obj ->" Delete from C_Customer where "
->"ID = @I "
|
:006BD1DC 6824D36B00 push 006BD324
* Possible StringData Ref from Code Obj ->" set @Count = @Count - 1 "
|
:006BD1E1 6854D36B00 push 006BD354
* Possible StringData Ref from Code Obj ->" end "
:006BD1E6 6878D36B00 push 006BD378
:006BD1EB 8D45F4 lea eax, dword ptr [ebp-0C]
:006BD1EE BA09000000 mov edx, 00000009
:006BD1F3 E8C883D4FF call 004055C0
:006BD1F8 EB43 jmp 006BD23D --------------------编程问答-------------------- 自己顶起
补充:.NET技术 , C#