哪位高手能给份Floyd算法的C#源码?能给出经过路径的
哪位高手能给份Floyd算法的C#源码?能给出经过路径的,谢谢!看文字看不太懂啊. --------------------编程问答-------------------- 这题不简单，我也要 --------------------编程问答-------------------- 有C的还怕没C#的？下面是我google的
#include<fstream>
#define Maxm 501
using namespace std;
ifstream fin("APSP.in");
ofstream fout("APSP.out");
int p,q,k,m;
int Vertex,Line[Maxm];
int Path[Maxm][Maxm],Map[Maxm][Maxm],Dist[Maxm][Maxm];
void Root(int p,int q)
{
if (Path[p][q]>0)
{
Root(p,Path[p][q]);
Root(Path[p][q],q);
}
else
{
Line[k]=q;
k++;
}
}
int main()
{
memset(Path,0,sizeof(Path));
memset(Map,0,sizeof(Map));
memset(Dist,0,sizeof(Dist));
fin >> Vertex;
for(p=1;p<=Vertex;p++)
for(q=1;q<=Vertex;q++)
{
fin >> Map[p][q];
Dist[p][q]=Map[p][q];
}
for(k=1;k<=Vertex;k++)
for(p=1;p<=Vertex;p++)
if (Dist[p][k]>0)
for(q=1;q<=Vertex;q++)
if (Dist[k][q]>0)
{
if (((Dist[p][q]>Dist[p][k]+Dist[k][q])||(Dist[p][q]==0))&&(p!=q))
{
Dist[p][q]=Dist[p][k]+Dist[k][q];
Path[p][q]=k;
}
}
for(p=1;p<=Vertex;p++)
{
for(q=p+1;q<=Vertex;q++)
{
fout << "\n==========================\n";
fout << "Source:" << p << '\n' << "Target " << q << '\n';
fout << "Distance:" << Dist[p][q] << '\n';
fout << "Path:" << p;
k=2;
Root(p,q);
for(m=2;m<=k-1;m++)
fout << "-->" << Line[m];
fout << '\n';
fout << "==========================\n";
}
}
fin.close();
fout.close();
return 0;
}
注解:无法连通的两个点之间距离为0;
Sample Input
7
00 20 50 30 00 00 00
20 00 25 00 00 70 00
50 25 00 40 25 50 00
30 00 40 00 55 00 00
00 00 25 55 00 10 70
00 70 50 00 10 00 50
00 00 00 00 70 50 00
Sample Output
==========================
Source:1
Target 2
Distance:20
Path:1-->2
==========================
==========================
Source:1
Target 3
Distance:45
Path:1-->2-->3
==========================
==========================
Source:1
Target 4
Distance:30
Path:1-->4
==========================
==========================
Source:1
Target 5
Distance:70
Path:1-->2-->3-->5
==========================
==========================
Source:1
Target 6
Distance:80
Path:1-->2-->3-->5-->6
==========================
==========================
Source:1
Target 7
Distance:130
Path:1-->2-->3-->5-->6-->7
==========================
==========================
Source:2
Target 3
Distance:25
Path:2-->3
==========================
==========================
Source:2
Target 4
Distance:50
Path:2-->1-->4
==========================
==========================
Source:2
Target 5
Distance:50
Path:2-->3-->5
==========================
==========================
Source:2
Target 6
Distance:60
Path:2-->3-->5-->6
==========================
==========================
Source:2
Target 7
Distance:110
Path:2-->3-->5-->6-->7
==========================
==========================
Source:3
Target 4
Distance:40
Path:3-->4
==========================
==========================
Source:3
Target 5
Distance:25
Path:3-->5
==========================
==========================
Source:3
Target 6
Distance:35
Path:3-->5-->6
==========================
==========================
Source:3
Target 7
Distance:85
Path:3-->5-->6-->7
==========================
==========================
Source:4
Target 5
Distance:55
Path:4-->5
==========================
==========================
Source:4
Target 6
Distance:65
Path:4-->5-->6
==========================
==========================
Source:4
Target 7
Distance:115
Path:4-->5-->6-->7
==========================
==========================
Source:5
Target 6
Distance:10
Path:5-->6
==========================
==========================
Source:5
Target 7
Distance:60
Path:5-->6-->7
==========================
==========================
Source:6
Target 7
Distance:50
Path:6-->7
--------------------编程问答-------------------- 还有1种方法，MATLAB7.0以上版本提供了deployment tools，可以将MATLAB的程序编译为DLL文件，脱离MATLAB环境执行。
LZ可以看看。
相关代码：
Matlab源代码为
function [D,R]=floyd(a)
n=size(a,1);
D=a
for i=1:n
for j=1:n
R(i,j)=j;
end
end
R
for k=1:n
for i=1:n
for j=1:n
if D(i,k)+D(k,j)<D(i,j)
D(i,j)=D(i,k)+D(k,j);
R(i,j)=R(i,k);
end
end
end
k
D
R
end
补充：.NET技术 , C#
