java 程序中打开文件和文件夹
打开文件
//打开工具的路径及名字
String toolsPath = "C:/WINDOWS/system32/notepad.exe ";
//被打开文件的路径及名字
String fileName = "test.txt";
try {
Runtime.getRuntime().exec(toolsPath+fileName);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
打开文件夹
try {
String[] cmd = new String[5];
String url = "C:/input";
cmd[0] = "cmd";
cmd[1] = "/c";
cmd[2] = "start";
cmd[3] = " ";
cmd[4] = url;
Runtime.getRuntime().exec(cmd);
} catch (IOException e) {
e.printStackTrace();
}
或者
Runtime.getRuntime().exec("cmd /c start C:/input");
摘自：yahohi的专栏
补充：软件开发 , Java ,
