用汇编的眼光看C++（之类静态变量、静态函数）
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看过设计模式的朋友都知道，我们在设计单件模式的时候离不开类的静态函数。和类的成员变量不同，类的静态变量属于全部类对象数据；同样和类的成员函数不同，类的静态函数属于全部类函数共有。这句话读来想来有一些拗口，不过没有关系，我们可以通过一段代码来说明问题。
（1）静态变量
老规矩，我们首先对类进行初步定义，如下所示：
class employee
{
public:
employee() { }
~employee() {}
static int value;
};
class employee
{
public:
employee() { }
~employee() {}
static int value;
}; 那么，这里出现的value是不是所共有的，我们可以看看相关的函数代码即可：
67: int employee::value = 0;
68:
69: void process()
70: {
00401240 push ebp
00401241 mov ebp,esp
00401243 push 0FFh
00401245 push offset __ehhandler$?process@@YAXXZ (0041f469)
0040124A mov eax,fs:[00000000]
00401250 push eax
00401251 mov dword ptr fs:[0],esp
00401258 sub esp,48h
0040125B push ebx
0040125C push esi
0040125D push edi
0040125E lea edi,[ebp-54h]
00401261 mov ecx,12h
00401266 mov eax,0CCCCCCCCh
0040126B rep stos dword ptr [edi]
71: employee m;
0040126D lea ecx,[ebp-10h]
00401270 call @ILT+35(employee::employee) (00401028)
00401275 mov dword ptr [ebp-4],0
72: employee n;
0040127C lea ecx,[ebp-14h]
0040127F call @ILT+35(employee::employee) (00401028)
73:
74: m.value = 10;
00401284 mov dword ptr [employee::value (00438494)],0Ah
75: n.value = 100;
0040128E mov dword ptr [employee::value (00438494)],64h
76: }
00401298 lea ecx,[ebp-14h]
0040129B call @ILT+0(employee::~employee) (00401005)
004012A0 mov dword ptr [ebp-4],0FFFFFFFFh
004012A7 lea ecx,[ebp-10h]
004012AA call @ILT+0(employee::~employee) (00401005)
004012AF mov ecx,dword ptr [ebp-0Ch]
004012B2 mov dword ptr fs:[0],ecx
004012B9 pop edi
004012BA pop esi
004012BB pop ebx
004012BC add esp,54h
004012BF cmp ebp,esp
004012C1 call __chkesp (004086b0)
004012C6 mov esp,ebp
004012C8 pop ebp
004012C9 ret
67: int employee::value = 0;
68:
69: void process()
70: {
00401240 push ebp
00401241 mov ebp,esp
00401243 push 0FFh
00401245 push offset __ehhandler$?process@@YAXXZ (0041f469)
0040124A mov eax,fs:[00000000]
00401250 push eax
00401251 mov dword ptr fs:[0],esp
00401258 sub esp,48h
0040125B push ebx
0040125C push esi
0040125D push edi
0040125E lea edi,[ebp-54h]
00401261 mov ecx,12h
00401266 mov eax,0CCCCCCCCh
0040126B rep stos dword ptr [edi]
71: employee m;
0040126D lea ecx,[ebp-10h]
00401270 call @ILT+35(employee::employee) (00401028)
00401275 mov dword ptr [ebp-4],0
72: employee n;
0040127C lea ecx,[ebp-14h]
0040127F call @ILT+35(employee::employee) (00401028)
73:
74: m.value = 10;
00401284 mov dword ptr [employee::value (00438494)],0Ah
75: n.value = 100;
00401
补充：软件开发 , C++ ,
