一个JS的问题,求大虾的帮助。谢谢~~
--------------------编程问答-------------------- 人在线, 求帮助了。 --------------------编程问答-------------------- http://www.cnblogs.com/atree/archive/2011/06/29/JS-JavaScript-Date-Format.html --------------------编程问答-------------------- 使用正则表达式将/替换成-然后取出前面10个字符 --------------------编程问答-------------------- Substring(0,10).Replace('/','-') --------------------编程问答--------------------还是没找到解决的方法。。。 --------------------编程问答--------------------
变量点Substring(0,10).Replace('/','-') ? --------------------编程问答--------------------
var a = type[i]["SUBMITTIME"]
alert(a);
a = a.Substring(0, 10).Replace('/', '-');
alert(a); --------------------编程问答--------------------
function test() {
var str = "2006/04/04 14:20:34";
var nowStr = new Date(str);
alert(nowStr.format("yyyy-MM-dd"));
}
Date.prototype.format = function (format) {
var o = {
"M+": this.getMonth() + 1, //month
"d+": this.getDate(), //day
"h+": this.getHours(), //hour
"m+": this.getMinutes(), //minute
"s+": this.getSeconds(), //second
"q+": Math.floor((this.getMonth() + 3) / 3), //quarter
"S": this.getMilliseconds() //millisecond
};
if (/(y+)/.test(format)) {
format = format.replace(RegExp.$1, (this.getFullYear() + "").substr(4 - RegExp.$1.length));
}
for (var k in o) {
if (new RegExp("(" + k + ")").test(format)) {
format = format.replace(RegExp.$1, RegExp.$1.length == 1 ? o[k] : ("00" + o[k]).substr(("" + o[k]).length));
}
}
return format;
};
输出2006-04-04 --------------------编程问答--------------------
function test() {
var str = "2006/04/04 14:20:34";
var nowStr = new Date(str);
alert(nowStr.format("yyyy-MM-dd"));
}
Date.prototype.format = function (format) {
var o = {
"M+": this.getMonth() + 1, //month
"d+": this.getDate(), //day
"h+": this.getHours(), //hour
"m+": this.getMinutes(), //minute
"s+": this.getSeconds(), //second
"q+": Math.floor((this.getMonth() + 3) / 3), //quarter
"S": this.getMilliseconds() //millisecond
};
if (/(y+)/.test(format)) {
format = format.replace(RegExp.$1, (this.getFullYear() + "").substr(4 - RegExp.$1.length));
}
for (var k in o) {
if (new RegExp("(" + k + ")").test(format)) {
format = format.replace(RegExp.$1, RegExp.$1.length == 1 ? o[k] : ("00" + o[k]).substr(("" + o[k]).length));
}
}
return format;
};
输出2006-04-04
补充:.NET技术 , C#