HDU 2255
二分图的最优匹配(最大权值)。用KM算法解决。纯模板。
下面是AC代码:
[cpp]
#include<cstdio>
#include<cstring>
using namespace std;
const int maxn = 305;
const int INF = (1<<30)-1;
int g[maxn][maxn];
int lx[maxn],ly[maxn];
int match[maxn];
bool visx[maxn],visy[maxn];
int slack[maxn];
int n;
bool dfs(int cur){
visx[cur] = true;
for(int y=1;y<=n;y++){
if(visy[y]) continue;
int t=lx[cur]+ly[y]-g[cur][y];
if(t==0){
visy[y] = true;
if(match[y]==-1||dfs(match[y])){
match[y] = cur;
return true;
}
}
else if(slack[y]>t){
slack[y]=t;
}
}
return false;
}
int KM(){
memset(match,-1,sizeof(match));
memset(ly,0,sizeof(ly));
for(int i=1 ;i<=n;i++){
lx[i]=-INF;
for(int j=1;j<=n;j++)
if(g[i][j]>lx[i]) lx[i]=g[i][j];
}
for(int x=1;x<=n;x++){
for(int i=1;i<=n;i++) slack[i]=INF;
while(true){
memset(visx,false,sizeof(visx));
memset(visy,false,sizeof(visy));
if(dfs(x)) break;
int d=INF;
for(int i=1;i<=n;i++){
if(!visy[i]&&d>slack[i]) d=slack[i];
}
for(int i=1;i<=n;i++){
if(visx[i]) lx[i]-=d;
}
for(int i=1;i<=n;i++){
if(visy[i]) ly[i]+=d;
else slack[i]-=d;
}
}
}
int result = 0;
for(int i = 1; i <=n; i++)
if(match[i]>-1)
result += g[match[i]][i];
return result;
}
int main(){
while(scanf("%d",&n)!=EOF){
int cost;
for(int i=1;i<=n;i++)
for(int j=1;j<=n;j++) {
scanf("%d",&cost);
g[i][j]=cost;
}
printf("%d\n",KM());
}
return 0;
}
补充:软件开发 , C++ ,