身份证限制正确输入的脚本

如题，jsp页面输入框标签s:textfield，想触发一个onkeydown事件。用脚本限制只能输入正确的身份证格式。望高手赐教O(∩_∩)O~（废话者and装懂蒙事者俺举报）

补充：说的就是JAVASCRIPT脚本- -！

答案：
可以用简单的正则表达式验证
document.getElementById("textfield").value.match(/d{17}[/dxX]|/d{15})
这样只能验证用户输入的是18位或15的数字 包括有的身份证最后两位是XX
如果要详细验证 下面是验证代码

private string CheckCidInfo(string cid)
  {
   string[] aCity = new string[]{null,null,null,null,null,null,null,null,null,null,null,"北京","天津","河北","山西","内蒙古",null,null,null,null,null,"辽宁","吉林","黑龙江",null,null,null,null,null,null,null,"上海","江苏","浙江","安微","福建","江西","山东",null,null,null,"河南","湖北","湖南","广东","广西","海南",null,null,null,"重庆","四川","贵州","云南","易做图",null,null,null,null,null,null,"陕西","甘肃","青海","宁夏","新疆",null,null,null,null,null,"台湾",null,null,null,null,null,null,null,null,null,"香港","澳门",null,null,null,null,null,null,null,null,"国外"};
   double iSum=0;
   string info="";
   System.Text.RegularExpressions.Regex rg = new System.Text.RegularExpressions.Regex(@"^\d{17}(\d|x)$");
   System.Text.RegularExpressions.Match mc = rg.Match(cid);
   if(!mc.Success)
   {
    return "";
   }   
   cid = cid.ToLower();
   cid = cid.Replace("x","a");
   if(aCity[int.Parse(cid.Substring(0,2))]==null)
   {
    return "非法地区";
   }
   try
   {
    DateTime.Parse(cid.Substring(6,4)+"-"+cid.Substring(10,2)+"-"+cid.Substring(12,2));
   }
   catch
   {
    return "非法生日";
   }
   for(int i=17;i>=0;i--)
   {    
    iSum +=(System.Math.Pow(2,i)%11)*int.Parse(cid[17-i].ToString(),System.Globalization.NumberStyles.HexNumber);

   }
   if(iSum%11!=1)
    return("非法证号");
   
   return(aCity[int.Parse(cid.Substring(0,2))]+","+cid.Substring(6,4)+"-"+cid.Substring(10,2)+"-"+cid.Substring(12,2)+","+(int.Parse(cid.Substring(16,1))%2==1?"男":"女"));
  
  }

调用测试：
Response.Write(CheckCidInfo("340524198002300019"));
Response.Write(CheckCidInfo("34052419800101001x"));

一般的网站还是用第一种好
用JAVASCRIPT脚本就可以写出来

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