android-调用本机的联系人界面及返回 - 随心

首先必加的权限<uses-permission android:name="android.permission.READ_CONTACTS" />

这里写两个方法。

方法一：本人在小米手机测试可以，不过在其他的手机测试发现返回的Uri为空，不知为何，于是找到了第二种方法来解决。

跳转至电话本
[java] www.zzzyk.com

Intent i = new Intent(Intent.ACTION_PICK);
i.setType("vnd.android.cursor.dir/phone");
startActivityForResult(i, SEND_SMS_TYPE);
返回获取数据

[java]

    @Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    switch (requestCode) {
    case SEND_SMS_TYPE:
        if(!(resultCode == RESULT_OK)){
            return ;
        }
        if (data == null) {
            return;
        }
        Uri uri = data.getData();
        Cursor cursor = getContentResolver().query(uri, null, null, null,
                null);
        cursor.moveToFirst();

        String number = cursor.getString(cursor
                .getColumnIndexOrThrow(Phones.NUMBER));
        sendAdrress = number;
        SEND_TYPE = SEND_SMS_TYPE;
        send_text_SMS.setText("发送短信" + " : " + number);

        break;
    }
    super.onActivityResult(requestCode, resultCode, data);
}
方法二：

[java]
Intent i = new Intent();
i.setAction(Intent.ACTION_PICK);
i.setData(ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(i, SEND_SMS_TYPE);
//-----------------------------------------------------------------
    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        switch (resultCode) {
        case RESULT_OK:
            switch (requestCode) {
            case SEND_SMS_TYPE:
                if (data == null) {
                    return;
                }
                String phoneNumber = null;
                Uri contactData = data.getData();
                if (contactData == null) {
                    return ;
                }
                Cursor cursor = managedQuery(contactData, null, null, null, null);
                if (cursor.moveToFirst()) {
//                  String name = cursor.getString(cursor
//                          .getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
                    String hasPhone = cursor
                            .getString(cursor
                                    .getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
                    String id = cursor.getString(cursor
                            .getColumnIndex(ContactsContract.Contacts._ID));
                    if (hasPhone.equalsIgnoreCase("1")) {
                        hasPhone = "true";
                    } else {
                        hasPhone = "false";
                    }
                    if (Boolean.parseBoolean(hasPhone)) {
                        Cursor phones = getContentResolver().query(
                                ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
                                null,
                                ContactsContract.CommonDataKinds.Phone.CONTACT_ID

补充：移动开发 , Android ,