Decode Ways
题目：
A message containing letters from A-Z is being encoded to numbers using the following mapping:
'A' -> 1
'B' -> 2
...
'Z' -> 26
Given an encoded message containing digits, determine the total number of ways to decode it.
For example,
Given encoded message "12",it could be decoded as "AB" (1 2) or "L" (12).
The number of ways decoding "12" is 2.
分析：可以用贪心的思想，而且当前数字只与前面的数字有关。
代码如下：
int numDecodings(string s) {
int n=s.size();
if(n==0)return 0;
int *result=new int[n+1];
memset(result,0,(n+1)*sizeof(int));
result[0]=1;
for(int i=1;i<=n;i++)
{
if(s[i-1]!='0')
{
result[i]+=result[i-1];
}
if(i>=2&&s[i-1]-'0'+10*(s[i-2]-'0')<=26&&s[i-1]-'0'+10*(s[i-2]-'0')>=10)
{
result[i]+=result[i-2];
}
}
return result[n];
}
补充：软件开发 , C++ ,
