HDU 4351

区间合并的线段树

#include<cstdio>
#include<algorithm>
#include<cstring>
#include<vector>
#define N 100100
#define f(x) ((x)==0?0:((x)%9==0?9:(x)%9))
using namespace std;

struct Tree{
    int l,r;
    int ls,rs,all,num;
}tree[5*N];
int val[N],mul[1125][1125];

void init(){
    int i,j,p,q;
    for(i=0;i<=1023;i++)
        for(j=i;j<=1023;j++){
            mul[i][j]=0;
            for(p=0;p<=9;p++)
                if(i&(1<<p))
                    for(q=0;q<=9;q++)
                        if(j&(1<<q))
                            mul[i][j]|=(1<<f(p+q));
            mul[j][i]=mul[i][j];
        }
}

void build(int s,int t,int id){
    tree[id].l=s,tree[id].r=t;
    if(s==t){
        tree[id].ls=tree[id].rs=tree[id].num=tree[id].all=1<<f(val[s]);
        return ;
    }
    int mid=(s+t)>>1;
    build(s,mid,id<<1);
    build(mid+1,t,id<<1|1);
    tree[id].all=tree[id<<1].all|tree[id<<1|1].all|mul[tree[id<<1].rs][tree[id<<1|1].ls]; //all表示所有情况
    tree[id].num=mul[tree[id<<1].num][tree[id<<1|1].num];      //num表示此区间内所有数和的digital root
    tree[id].ls=tree[id<<1].ls|mul[tree[id<<1].num][tree[id<<1|1].ls]; //ls表示所有含有区间左端点的区间的情况
    tree[id].rs=tree[id<<1|1].rs|mul[tree[id<<1|1].num][tree[id<<1].rs];//rs表示所有含有区间右端点的区间的情况
}

struct Tree query(int s,int t,int id){
    struct Tree t1,t2,t3;
    if(tree[id].l==tree[id].r)return tree[id];
    if(tree[id].l==s && tree[id].r==t)return tree[id];
    int mid=(tree[id].l+tree[id].r)>>1;
    if(mid>=t)return query(s,t,id<<1);
    else if(mid<s)return query(s,t,id<<1|1);
    else{
        t1=query(s,mid,id<<1);
        t2=query(mid+1,t,id<<1|1);
        t3.all=t1.all|t2.all|mul[t1.rs][t2.ls];
        t3.num=mul[t1.num][t2.num];
        t3.ls=t1.ls|mul[t1.num][t2.ls];
        t3.rs=t2.rs|mul[t2.num][t1.rs];
        return t3;
    }
}

int main(){
    int t,T,n,q;
    int i,j,l,r;
    init();
    scanf("%d",&T);
    for(t=1;t<=T;t++){
        scanf("%d",&n);
        for(i=1;i<=n;i++)scanf("%d",&val[i]);
        build(1,n,1);
        scanf("%d",&q);
        printf("Case #%d:\n",t);
        for(j=1;j<=q;j++){
            scanf("%d %d",&l,&r);
            struct Tree tem=query(l,r,1);
            int num=1;
            vector<int>vec;
            vec.clear();
            for(i=9;i>=0 && num<=5;i--){
                if(tem.all&(1<<i)){
                    num++;
                    vec.push_back(i);
                }
            }
            while(num<=5){
                vec.push_back(-1);
                num++;
            }
            for(i=0;i<vec.size();i++){
                if(!i)printf("%d",vec[i]);
                else printf(" %d",vec[i]);
            }
            puts("");
        }
        if(t!=T)puts("");
    }
    return 0;
}

补充：软件开发 , C++ ,