汽车加油问题：java版算法设计与分析

import java.io.*;

class Problem
{
//加油站间距           加油站点        加满油后行驶的路程
    public int Greedy(int distance[], int note[], int n)
    { //s--行驶的路程
        int i, j, s, add = 0, p = 0, k = distance.length;
        for (i = 0; i < k; i++)
        {
            if (distance[i] > n)
            {//不能到达目的地
                return -1;
            }
        }
        for (j = 0, s = 0; j < k; j++)
        {
            s = s+distance[j];
            if (s > n)
            {//需要加油
                add++;
                note[p++] = j;
                s = distance[j];
            }
        }
        return add;
    }

}

public class RefuelCar {

public static void main(String[] args) throws IOException
{
     int n,k;
     int count=0;//加油次数 www.zzzyk.com
     BufferedReader br=new BufferedReader(new InputStreamReader(System.in));


   System.out.println("请输入汽车加满油后可行驶路程：");
   String str=br.readLine();
      n=Integer.parseInt(str);

    System.out.println("请输入途经加油站总数：");
    String str_k=br.readLine();
    k=Integer.parseInt(str_k);



    int distance[]=new int[k+1];//加油站间距
    int note[] = new int[k];//记录加油站点

    for(int i=0;i<=k;i++)
    {
    System.out.println("请输入加油站"+(i)+"到加油站"+(i+1)+"间距");
    String temp=br.readLine();
    distance[i]=Integer.parseInt(temp.toString());
    }

    Problem p=new Problem();
    count=p.Greedy(distance, note,n);
    if (count >= 0)
       {
           if (count == 0)
               System.out.println("汽车不用加油就可到达终点！");
           else
           {
               System.out.println("汽车在旅途中需加"+count+"次油！");
               System.out.println("分别在以下加油站加了油：");
               for (int i = 0; i < note.length; i++)
               {
                   if (note[i] != 0)
                   {//输出需加油站点
                    System.out.println("第" + note[i] + "个加油站！");
                   }
               }
           }
       }
       else
        System.out.println("汽车无法到达终点！");

   }

}

摘自 spy1403414807的专栏

补充：软件开发 , Java ,