类函数指针和普通函数指针
我们都看惯了一般的函数指针,但是关于类的函数指针又是怎样的呢?它的静态函数指针和非静态函数指针是一样的么?<span style="font-size:18px">#include<iostream> using namespace std; typedef int(*pMax)(int,int);//普通函数指针 int max(int a,int b) { <span style="white-space:pre"> </span>return a>b?a:b; } class A { public: <span style="white-space:pre"> </span>int min(int a,int b) <span style="white-space:pre"> </span>{ <span style="white-space:pre"> </span>return a<b?a:b; <span style="white-space:pre"> </span>} <span style="white-space:pre"> </span>static int myMin(int a,int b) <span style="white-space:pre"> </span>{ <span style="white-space:pre"> </span>return a<b?a:b; <span style="white-space:pre"> </span>} }; class B:public A { }; typedef int (A::*pMin)(int,int);//类的非静态函数指针 typedef int (*pMyMin)(int,int);//类的静态函数指针 typedef int (B::*pMinB)(int,int);//类的非静态函数指针 void main() { <span style="white-space:pre"> </span>int a=3; <span style="white-space:pre"> </span>int b=4; <span style="white-space:pre"> </span> <span style="white-space:pre"> </span>cout<<max(a,b)<<endl; <span style="white-space:pre"> </span>/* 测试普通函数指针 */ <span style="white-space:pre"> </span>pMax p1=&max; <span style="white-space:pre"> </span>cout<<(*p1)(a,b)<<endl; <span style="white-space:pre"> </span>int (*p2)(int, int)=&max; <span style="white-space:pre"> </span>cout<<(*p2)(a,b)<<endl; <span style="white-space:pre"> </span>/* 测试类的非静态函数指针 */ <span style="white-space:pre"> </span>A TestA; <span style="white-space:pre"> </span>pMin p3=&A::min; <span style="white-space:pre"> </span>cout<<(TestA.*p3)(a,b)<<endl; <span style="white-space:pre"> </span>int(A::*p4)(int,int)=&A::min; <span style="white-space:pre"> </span>cout<<(TestA.*p4)(a,b)<<endl; <span style="white-space:pre"> </span> <span style="white-space:pre"> </span>/* 测试类的静态函数指针 */ <span style="white-space:pre"> </span>pMyMin p5=&A::myMin; <span style="white-space:pre"> </span>cout<<(*p5)(a,b)<<endl; <span style="white-space:pre"> </span>int(*p6)(int,int)=&A::myMin; <span style="white-space:pre"> </span>cout<<(*p6)(a,b)<<endl; <span style="white-space:pre"> </span>/* 测试非静态函数指针在类继承中怎么使用 */ <span style="white-space:pre"> </span>B TestB; <span style="white-space:pre"> </span>pMinB p7=&A::min; <span style="white-space:pre"> </span>cout<<(TestB.*p7)(a,b)<<endl; <span style="white-space:pre"> </span>cout<<(TestB.*p3)(a,b)<<endl; //<span style="white-space:pre"> </span>cout<<(TestA.*p7)(a,b)<<endl;错误 }</span>
从中可以看出,父类对象不可以调用以子类声明的函数指针,而子类对象可以调用以父类声明的函数指针。
补充:软件开发 , C++ ,