Zigzag Conversion
Question ：The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
Anwser 1 ：
[cpp]
class Solution {
public:
string convert(string s, int nRows) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
string ret(s);
int stepArray[2];
int steps = 2 * nRows - 2;
int retSize = 0;
for(int i = 0; i < nRows; i++)
{
int num = nRows - (i + 1) + nRows - (i + 1) - 1;
num++;
stepArray[0] = num;
if (stepArray[0] == 0)
stepArray[0] = steps;
stepArray[1] = steps - num;
if (stepArray[1] == 0)
stepArray[1] = steps;
int j = i;
int index = 0;
while(j < s.size())
{
ret[retSize++] = s[j];
if (j == j + stepArray[index])
break;
j = j + stepArray[index];
index = 1 - index;
}
}
return ret;
}
};
Anwser 2 ：
[cpp]
class Solution {
public:
string convert(string s, int nRows) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if (nRows == 1) return s;
vector<vector<char>> v(nRows, vector<char>());
int i = 0;
int d = 0;
for (int j = 0; j < s.size(); j++) {
v[i].push_back(s[j]);
if (d == 0) {
if (i + 1 == nRows) {
i--;
d = 1;
} else {
i++;
}
} else {
if (i == 0) {
i++;
d = 0;
} else {
i--;
}
}
}
string ret = "";
for (int j = 0; j < nRows; j++) {
for (int k = 0; k < v[j].size(); k++)
ret += v[j][k];
}
return ret;
}
};
补充：综合编程 , 其他综合 ,
