为什么我返回的值是“0”?
--------------------编程问答-------------------- Function jiang(zx, zj) as string--------------------编程问答-------------------- 另外需要跟下程序看是不是中间退出函数了。 --------------------编程问答-------------------- 这次显示是“#value” --------------------编程问答-------------------- --------------------编程问答-------------------- --------------------编程问答-------------------- 单步执行 跟踪一下 --------------------编程问答-------------------- 你还是给出输入的值 让大家能够帮你分析 --------------------编程问答-------------------- zx = 2041020283011
zj = 10111213262811
--------------------编程问答-------------------- Mod 参与运算的表达式的值不能超过长整型范围。
求余改为:
x-int(x/y)
--------------------编程问答-------------------- For i = 1 To 6
For j = 1 To 6
If r(i) = jr(j) Then
p = p + 1
End If
Next j
Next i
//此时i=6,j=6
r(i) = (zx Mod 10 ^ (8 - i) - zx Mod 10 ^ (7 - i)) / 10 ^ (7 - i)
//相当于r(6)=(zx mod 10^2-zx mod 10^1)/10^1
b = zx Mod 10 ^ 2
jr(i) = (zj Mod 10 ^ (8 - i) - zj Mod 10 ^ (7 - i)) / 10 ^ (7 - i)
//相当于jr(6)=(zj mod 10^2-zj mod 10^1)/10^1
jb = zj Mod 10 ^ 2
--------------------
不知道你这是要干什么... --------------------编程问答-------------------- zx = 2041020283011
zj = 10111213262811
Function jiang(zx, zj)
If zx - 10 ^ 12 < 0 Then
jiang = "自选错误"
Exit Function
End If
If zj - 10 ^ 12 < 0 Then
jiang = "中奖号错误"
Exit Function
End If
Dim r(6) As Single
Dim jr(6) As Single
Dim b, jb, p, i, j
b = zx Mod 10 ^ 2
jb = zj Mod 10 ^ 2
p = 0
For i = 1 To 6
r(i) = (Int(zx / 10 ^ (2 * (8 - i))) - Int(zx / 10 ^ (2 * (7 - i)))) / (10 ^ (7 - i))
For j = 1 To 6
jr(j) = (Int(zj / 10 ^ (2 * (8 - j))) - Int(zj / 10 ^ (2 * (7 - j)))) / (10 ^ (7 - j))
If r(i) = jr(j) Then p = p + 1
Next j
Next i
If b = jb Then
If p = 6 Then
jiang = "一等奖"
ElseIf p = 5 Then
jiang = "三等奖"
ElseIf p = 4 Then
jiang = "四等奖"
ElseIf p = 3 Then
jiang = "五等奖"
ElseIf p < 3 Then
jiang = "六等奖"
End If
Else
If p = 6 Then
jiang = "二等奖"
ElseIf p = 5 Then
jiang = "四等奖"
ElseIf p = 4 Then
jiang = "五等奖"
ElseIf p < 4 Then
jiang = "未中奖"
End If
End If
End Function
返回值“value”
--------------------编程问答-------------------- --------------------编程问答-------------------- 下次再也不敢抽奖了
补充:VB , 基础类