利用c++设计一个算法解决对单链表的操作

答案：// file chain.h
#ifndef Chain_
#define Chain_
#include <iostream.h>
template <class T> class Chain;
template <class T>
class ChainNode {
   friend Chain<T>;
   private:
      T data;
      ChainNode<T> *link;
};
template<class T>
class Chain {
   public:
      Chain() {first = 0;}
      ~Chain();
      bool IsEmpty() const {return first == 0;}
      int Length() const; 
      bool Find(int k, T& x) const; 
      int Search(const T& x) const; 
      Chain<T>& Delete(int k, T& x); 
      Chain<T>& Insert(int k, const T& x);
      void Output(ostream& out) const;
   private:
      ChainNode<T> *first;  // pointer to first node
};
template<class T>
Chain<T>::~Chain()
{// Chain destructor. Delete all nodes in chain.
   ChainNode<T> *next;  // next node
   while (first) {
      next = first->link;
      delete first;
      first = next;
      }
}
template<class T>
int Chain<T>::Length() const
{// Return the number of elements in the chain.
   ChainNode<T> *current = first;
   int len = 0;
   while (current) {
     len++;
     current = current->link;
     }
   return len;
}
template<class T>
bool Chain<T>::Find(int k, T& x) const
{// Set x to the k'th element in the chain.
 // Return false if no k'th; return true otherwise.
   if (k < 1) return false;
   ChainNode<T> *current = first;
   int index = 1;  // index of current
   while (index < k && current) {
      current = current->link;
      index++;
      }
   if (current) {x = current->data;
                 return true;}
   return false; // no k'th element
}
template<class T>
int Chain<T>::Search(const T& x) const
{// Locate x.  Return position of x if found.
 // Return 0 if x not in the chain.
   ChainNode<T> *current = first;
   int index = 1;  // index of current
   while (current && current->data != x) {
      current = current->link;
      index++;
      }
   if (current) return index;
   return 0;
}
template<class T>
Chain<T>& Chain<T>::Delete(int k, T& x)
{// Set x to the k'th element and delete it.
 // Throw OutOfBounds exception if no k'th element.
   if (k < 1 || !first)
      throw OutOfBounds(); // no k'th
   
   // p will eventually point to k'th node
   ChainNode<T> *p = first;
   // move p to k'th & remove from chain
   if (k == 1) // p already at k'th
      first = first->link; // remove
   else { // use q to get to k-1'st
      ChainNode<T> *q = first;
      for (int index = 1; index < k - 1 && q;
                          index++)
         q = q->link;
      if (!q || !q->link)
         throw OutOfBounds(); // no k'th
      p = q->link; // k'th
      q->link = p->link;} // remove from chain
   // save k'th element and free node p
   x = p->data;
   delete p;
   return *this;
}
template<class T>
Chain<T>& Chain<T>::Insert(int k, const T& x)
{// Insert x after the k'th element.
 // Throw OutOfBounds exception if no k'th element.
 // Pass NoMem exception if inadequate space.
   if (k < 0) throw OutOfBounds();
   // p will eventually point to k'th node
   ChainNode<T> *p = first;
   for (int index = 1; index < k && p;
                       index++)  // move p to k'th
      p = p->link;
   if (k > 0 && !p) throw OutOfBounds(); // no k'th
   // insert
   ChainNode<T> *y = new ChainNode<T>;
   y->data = x;
   if (k) {// insert after p
           y->link = p->link;
           p->link = y;}
   else {// insert as first element
         y->link = first;
         first = y;}
   return *this;
}
template<class T>
void Chain<T>::Output(ostream& out) const
{// Insert the chain elements into the stream out.
   ChainNode<T> *current;
   for (current = first; current;
                         current = current->link)
      out << current->data << "  ";
}
// overload <<
template <class T>
ostream& operator<<(ostream& out, const Chain<T>& x)
   {x.Output(out); return out;}
#endif

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