数字转换为中文的类。（今晚的无聊之作）

答案：<?php
// 诸海加
// 2000-7-19

class ChineseNumber
{
    var $basical=array(0=>"零","一","二","三","四","五","六","七","八","九");
    //var $basical=array(0=>"零","壹","贰","叁","肆","伍","陆","柒","捌","玖");
    var $advanced=array(1=>"十","百","千");
    //var $advanced=array(1=>"拾","佰","仟");
    var $top=array(1=>"万","亿");

    var $level;            // 以4位为一级

    // 先实现万一下的数的转换
    function ParseNumber($number)
    {
        if ($number>999999999999)        // 只能处理到千亿。
            return "数字太大，无法处理。抱歉！";
        if ($number==0)
            return "零";

        for($this->level=0;$number>0.0001;$this->level++,$number=floor($number / 10000))
        {
            // 对于中文来说，应该是4位为一组。
            // 四个变量分别对应 个、十、百、千 位。
            $n1=substr($number,-1,1);
            if($number>9)
                $n2=substr($number,-2,1);
            else
                $n2=0;
            if($number>99)
                $n3=substr($number,-3,1);
            else
                $n3=0;
            if($number>999)
                $n4=substr($number,-4,1);
            else
                $n4=0;

            if($n4)
                $parsed[$this->level].=$this->basical[$n4].$this->advanced[3];
            else
                if(($number/10000)>=1)        // 千位为0，数值大于9999的情况
                    $parsed[$this->level].="零";
            if($n3)
                $parsed[$this->level].=$this->basical[$n3].$this->advanced[2];
            else
                if(!ereg("零$",$parsed[$this->level]) && ($number / 1000)>=1)    // 不出现连续两个“零”的情况
                    $parsed[$this->level].="零";
            if($n2)
                $parsed[$this->level].=$this->basical[$n2].$this->advanced[1];
            else
                if(!ereg("零$",$parsed[$this->level]) && ($number / 100)>=1)    // 不出现连续两个“零”的情况
                    $parsed[$this->level].="零";
            if($n1)
                $parsed[$this->level].=$this->basical[$n1];
        }
        for($this->level-=1;$this->level>=0;$this->level--)
        {
            $result.=$parsed[$this->level].$this->top[$this->level];
        }

        if(ereg("零$",$result))
            $result=substr($result,0,strlen($result)-2);

        return $result;
        
    }
};

$c=new ChineseNumber();
echo $c->ParseNumber(123456789012);

?>

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