刚解除asp，想玩一下asp的异步调用，照着别人的代码写了半天，调试不报错，就是不出想要的结果，郁闷中，谁能给我个简单的asp+ajax调用的示例。要求：1.需要连接access数据库
2.需要使用到ajax异步调用
代码越简单越好，最终实现的效果就是点一个按钮，从数据库里面捞一条数据，然后显示到页面上，利用ajax实现页面无刷新。
源代码最好发QQ邮箱 tianhewulei@qq.com，各位大侠万分感谢，最好在程序上多写点注释，asp语法相当不熟
补充：只要基本功能，数据库一张表，一个字段即可，页面一个按钮，一个显示结果的地方即可，各位大虾帮帮忙啊答案：index.htm''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
<%@LANGUAGE="VBSCRIPT" CODEPAGE="65001"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>PROTOTYPE POST</title>
<script language="javascript" type="text/javascript" src="prototype.js"></script>
</head>
<body>
<script type="text/javascript">
function postNewContact(){
var form = $('form');
var name = $('uin');
var url = '2.asp';
var myAjax = new Ajax.Request(url,{method:'post',
parameters: Form.serialize(form),
onComplete:showResponse});
}
function showResponse(originalRequest){
DisplayDIV.innerHTML+=originalRequest.responseText;
}
</script>
<form method="post" id="form" name="form">
<input type="text" name="uin">
<input onclick="postNewContact();" name="pbut" type="button" value="POST" />
<div id="DisplayDIV"></div>
</form>
</body>
</html>''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
-------------------------------------------------
2.asp
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
<%
set conn=server.createobject("adodb.connection")
conn.open "Provider=Microsoft.Jet.OLEDB.4.0;User Id=admin;jet OleDB:Database Password=;Data Source="& Server.MapPath("/data.asp")
exec="select * from file where id = " +request("uin")
set rs=server.createobject("adodb.recordset")
rs.open exec,conn,1,1
if rs.eof then
Response.write "Id Err!"
else
do while not rs.eof
%><%=rs("name")%><%
rs.movenext
loop
end if
rs.close
set rs=nothing
conn.close
set conn=nothing
%><br>''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
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