C语言高手帮帮忙

编制一个统计存储在文件中的学生考试分数的管理程序。设学生成绩以一个学生一条记录的形式存储在文件中，每个学生记录包含的信息有姓名、学号和数学、语文和英语三门功课的成绩。要求编制具有以下几项功能的程序：求出各门课程的平均分；在屏幕上显示全部学生成绩；按总分由高到低显示学生信息（用冒泡排序法排序···）。

答案：#include "stdio.h"
 struct student
 { char name[12];
   int num;
   int grade[3];
   }stu[3];
  
int inputgrade()
 {  int i; FILE *fp;
    if((fp=fopen("b.txt","r"))==NULL)
  
{ printf("cannot open file.\
");
  
  exit(0); }
    for(i=0;i<3;i++)
    fscanf(fp,"%s %d %d %d %d",stu[i].name,&stu[i].num,&stu[i].grade[0],&stu[i].grade[1],&stu[i].grade[2]);
    printf("The grade has enter.\
");
    fclose(fp);
    }
 int outputgrade()
 {  int i;
    printf(" the grade is:\
");
    for(i=0;i<3;i++)
   {  printf("%s %d %d %d %d",stu[i].name,stu[i].num,stu[i].grade[0],stu[i].grade[1],stu[i].grade[2]);
  
printf("\
");  }
    }
  
int average()
 { int  i,j;  float sum,aver;
  
for(j=0;j<3;j++)
  
{   sum=0; aver=0;
  
   for(i=0;i<3;i++)
  
  { sum=sum+stu[i].grade[j]; }
  
  
aver=sum/3.0;
  
  printf("The %d  grade average is %f.\
",j,aver); }
   return 0;
  
} 
    int maopaosort()
 {
int i,j,k,t,gra[9];
  
for(k=0;k<3;k++)
  
  gra[k]=stu[0].grade[k];
  
for(k=3;k<6;k++)
  
  gra[k]=stu[1].grade[k-3];
  
for(k=6;k<9;k++)
  
  gra[k]=stu[2].grade[k-6];
  
    for(j=0;j<8;j++)
  
for(i=0;i<8-j;i++)
   if(gra[i+1]<gra[i])
   {
    t=gra[i];
   gra[i]=gra[i+1];
    gra[i+1]=t;
   }
 printf("the sort number is:\
 ");
 for(k=8;k>=0;k--)
 for(i=0;i<3;i++)
 for(j=0;j<3;j++)
 if(gra[k]==stu[i].grade[j])
 printf("%d %s %d\
",gra[k],stu[i].name,stu[i].num);
  
 }
  
main()
 {  int s,i,flag,l;
    int pass[4];
    printf("This is a performance management system:\
");
    for(l=0;l<3;l++)
    {  flag=0;
  
 printf("
  
  
 please enter the password: ");
    scanf("%1d%1d%1d%1d",&pass[0],&pass[1],&pass[2],&pass[3]);
    for(i=0;i<4;i++)
    if(pass[i]==i+1)  flag=flag+1;
    if(flag==4) {  printf("You enter the  performance management system:\
");
  
  
  
    printf("they are four choose:\
");
  
  
  
    printf("choose one is grade input,enter choose one,please enter 1 :\
");
  
  
  
    printf("choose two is grade output,enter choose two,please enter 2 :\
");
  
  
  
    printf("choose three is grade average,enter choose three,please enter 3 :\
");
  
  
  
    printf("choose three is grade sort,enter choose four,please enter 4 :\
");
  
  
  
    for(i=0;i<5;i++)
  
  
  
   { printf("please enter you choose: ");
  
  
  
    scanf("%d",&s);
  
  
  
    printf("\
");
  
  
  
  switch(s)
  
  
  
 {case 1:inputgrade();break;
  
  
  
  case 2:outputgrade();break;
  
  
  
  case 3:average();break;
  
  
  
  case 4:maopaosort();break;
  
  
  
 default :printf("you enter choose is wrong.\
"); }
  
  
    }
   }
  
 else printf("the password is wrong.\
") ; }
    getch();
    }
  
  
   这个我已经调试好了
要源程序的话hi我
   进入系统的密码是1234
    b.txt 中的内容是
  
  
  
   liudenghua 2021 89 78 67
 guofucheng 2022 99 98 97
 zhangxueyou 2023 88 87 76
  
 刚才又改了一下  刚才有个功能没实现 就是冒泡法后输出学生信息
 现在改好了  要是有什么问题  hi我就OK了
嗯 报酬呢？

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