编程经验不足，请高手帮忙将两程序整合
本人编程经验不足，请高手帮忙将两程序整合，一个是后台算法，一个是界面。请大家帮帮忙吧！ 新人在此先谢过大家using System;
using System.Collections.Generic;
using System.Text;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string[][] lines = new string[5][];
lines[0] = new string[] { "A", "C", "E", "G", "I", "K", "M", "O" };
lines[1] = new string[] { "B", "D", "F", "H", "J", "L", "N", "P" };
lines[2] = new string[] { "A", "C", "E", "L", "Q", "W" };
lines[3] = new string[] { "B", "E", "F", "J", "Q", "L", "M", "H" };
lines[4] = new string[] { "E", "C", "L", "H", "J", "M", "O" };
string start = "A", end = "L", change;
int startID, endID, changeIDinStartLine, changeIDinEndLine;
int startLineID, endLineID;
int stopsCount = 0;
int solutionsCount = 0;
Console.WriteLine("We've got " + lines.Length + " line(s) in total:");
for (int i = 0; i < lines.Length; i++)
{
Console.Write("line[" + i + "]:");
for (int j = 0; j < lines[i].Length; j++)
Console.Write(lines[i][j] + " ");
Console.WriteLine();
}
Console.WriteLine("\n\nNow you are going FROM [" + start + "] TO [" + end + "]\n\n");
for (startLineID = 0; startLineID < lines.Length; startLineID++)
{
//依次测试每条线路，判断起点是否在其中
startID = belongTo(start, lines[startLineID]);
if (startID >= 0)//一条包含起点的线路
{
//判断终点是否也在此线路中
endID = belongTo(end, lines[startLineID]);
if (endID >= 0)//终点也在此线路中
{
stopsCount = Math.Abs(startID - endID);
Console.WriteLine("Solution(" + (++solutionsCount) + "): start from [" + start + "] in line[" + startLineID + "] end at [" + end + "]\n" + stopsCount + " stop(s)\n");
continue;//跳过剩余操作，直接回到最外层循环，判断起点是否在余下的线路中
}
//终点和起点不在一条线路中时，需要测试终点是否在其他线路
for (endLineID = 0; endLineID < lines.Length; endLineID++)
{
//依次测试每条线路，判断终点是否在其中
endID = belongTo(end, lines[endLineID]);
if (endID >= 0)
//起点线路中，除了起点之外的其他站点依次进行测试，判断是否在终点线路中
for (changeIDinStartLine = 0; changeIDinStartLine < lines[startLineID].Length; changeIDinStartLine++)
{
if (changeIDinStartLine != startID)
{
change = lines[startLineID][changeIDinStartLine];
changeIDinEndLine = belongTo(change, lines[endLineID]);
if (changeIDinEndLine >= 0)
{
stopsCount = Math.Abs(startID - changeIDinStartLine) + Math.Abs(endID - changeIDinEndLine);
Console.WriteLine("Solution(" + (++solutionsCount) + "): start from [" + start + "] in line[" + startLineID + "] change at [" + change + "] to line[" + endLineID + "] end at [" + end + "]\n" + stopsCount + " stop(s)\n");
}
}
}
}
}
}
Console.WriteLine("\n(" + solutionsCount + ") solution(s)");
}
//判断站点是否属于某线路的方法：是，返回站点在线路中的数组下标；否，返回-1
static int belongTo(string target, string[] line)
{
for (int i = 0; i < line.Length; i++)
if (line[i] == target)
return i;
return -1;
}
}
}
这个是后台算法
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
namespace 公交查询系统__2._1_
{
public partial class Form1 : Form
{
static string[] arrd = { "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q" }, arrh ={ "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q" };
public Form1()
{
InitializeComponent();
}
private void comboBox1_SelectedIndexChanged(object sender, EventArgs e)
{
this.richTextBox1.Text = this.comboBox1.GetItemText(this.comboBox1.SelectedItem);
this.richTextBox1.Text = doit(this.comboBox1.GetItemText(this.comboBox1.SelectedItem), this.comboBox2.GetItemText(this.comboBox2.SelectedItem));
}
private void comboBox2_SelectedIndexChanged(object sender, EventArgs e)
{
this.richTextBox1.Text = this.comboBox2.GetItemText(this.comboBox2.SelectedItem);
this.richTextBox1.Text = doit(this.comboBox1.GetItemText(this.comboBox1.SelectedItem), this.comboBox2.GetItemText(this.comboBox2.SelectedItem));
}
private void richTextBox1_TextChanged(object sender, EventArgs e)
{
}
private string doit(string start, string end) { return "result"; }
}
}
这个是界面
谢谢大家了！！
--------------------编程问答-------------------- 帮顶一下!! --------------------编程问答-------------------- 顶顶。 --------------------编程问答-------------------- 你这是在做什么?要做什么?要整合什么?看不懂你在干什么. --------------------编程问答-------------------- 帮顶 --------------------编程问答-------------------- 是不是有病啊 --------------------编程问答-------------------- 一个控制台程序一个WINFORM程序..
汗.... --------------------编程问答-------------------- 把 static void Main(string[] args) 做个第二个程序里的函数不就行了么？
--------------------编程问答-------------------- 不太清楚你要取用控制台的哪个变量？还是要取用string[] args ，还是取用。。。？
你就直接改成模板类算了，全设成公共函数，然后自己调用。
class Programs'这里改个名字，以防冲突
{
public static void Mains(string[] args)
{
string[][] lines = new string[5][];
lines[0] = new string[] { "A", "C", "E", "G", "I", "K", "M", "O" };
lines[1] = new string[] { "B", "D", "F", "H", "J", "L", "N", "P" };
lines[2] = new string[] { "A", "C", "E", "L", "Q", "W" };
lines[3] = new string[] { "B", "E", "F", "J", "Q", "L", "M", "H" };
lines[4] = new string[] { "E", "C", "L", "H", "J", "M", "O" };
string start = "A", end = "L", change;
int startID, endID, changeIDinStartLine, changeIDinEndLine;
int startLineID, endLineID;
int stopsCount = 0;
int solutionsCount = 0;
Console.WriteLine("We've got " + lines.Length + " line(s) in total:");
for (int i = 0; i < lines.Length; i++)
{
Console.Write("line[" + i + "]:");
for (int j = 0; j < lines[i].Length; j++)
Console.Write(lines[i][j] + " ");
Console.WriteLine();
}
Console.WriteLine("\n\nNow you are going FROM [" + start + "] TO [" + end + "]\n\n");
for (startLineID = 0; startLineID < lines.Length; startLineID++)
{
//依次测试每条线路，判断起点是否在其中
startID = belongTo(start, lines[startLineID]);
if (startID > = 0)//一条包含起点的线路
{
//判断终点是否也在此线路中
endID = belongTo(end, lines[startLineID]);
if (endID > = 0)//终点也在此线路中
{
stopsCount = Math.Abs(startID - endID);
Console.WriteLine("Solution(" + (++solutionsCount) + "): start from [" + start + "] in line[" + startLineID + "] end at [" + end + "]\n" + stopsCount + " stop(s)\n");
continue;//跳过剩余操作，直接回到最外层循环，判断起点是否在余下的线路中
}
//终点和起点不在一条线路中时，需要测试终点是否在其他线路
for (endLineID = 0; endLineID < lines.Length; endLineID++)
{
//依次测试每条线路，判断终点是否在其中
endID = belongTo(end, lines[endLineID]);
if (endID > = 0)
//起点线路中，除了起点之外的其他站点依次进行测试，判断是否在终点线路中
for (changeIDinStartLine = 0; changeIDinStartLine < lines[startLineID].Length; changeIDinStartLine++)
{
if (changeIDinStartLine != startID)
{
change = lines[startLineID][changeIDinStartLine];
changeIDinEndLine = belongTo(change, lines[endLineID]);
if (changeIDinEndLine > = 0)
{
stopsCount = Math.Abs(startID - changeIDinStartLine) + Math.Abs(endID - changeIDinEndLine);
Console.WriteLine("Solution(" + (++solutionsCount) + "): start from [" + start + "] in line[" + startLineID + "] change at [" + change + "] to line[" + endLineID + "] end at [" + end + "]\n" + stopsCount + " stop(s)\n");
}
}
}
}
}
}
Console.WriteLine("\n(" + solutionsCount + ") solution(s)");
}
//判断站点是否属于某线路的方法：是，返回站点在线路中的数组下标；否，返回-1
public static int belongTo(string target, string[] line)
{
for (int i = 0; i < line.Length; i++)
if (line[i] == target)
return i;
return -1;
}
}
}
补充：.NET技术 , C#
