当前位置:编程学习 > C/C++ >>

UVa 10173 - Smallest Bounding Rectangle

题目:求包裹平面上已知点的最小面积矩形。
分析:计算几何、凸包、旋转卡壳。最小面积矩形一定存在一条边与凸包共线。(不共线时,可以通过旋转变得更小)
            根据以上结论,直接枚举底边,然后利用旋转卡壳确定其余三个顶点即可。
              
             如图:L1为底边,初始化确定四个边界点,然后利用向量,控制L2,L3,L4与L1的角度即可。
注意:1.输入点可以小于3个,可能是点或者线段;
            2.精度问题,之前用点到直线距离公式WA了N久,换成向量计算就AC了。
 
#include <algorithm>  
#include <iostream>  
#include <cstdlib>  
#include <cstdio>  
#include <cmath>  
  
#define esp 1e-6  
  
using namespace std;  
  
//点结构   
typedef struct pnode  
{  
    double x,y,d;  
    pnode( double a, double b ){x = a;y = b;}  
    pnode(){}  
}point;  
point P[ 1005 ];  
  
//直线结构   
typedef struct lnode  
{  
    double x,y,dx,dy;  
    lnode( point a, point b ){x = a.x;y = a.y;dx = b.x-a.x;dy = b.y-a.y;}  
    lnode(){}  
}line;  
  
//叉乘ab*ac   
double crossproduct( point a, point b, point c )  
{  
    return (b.x-a.x)*(c.y-a.y)-(c.x-a.x)*(b.y-a.y);   
}  
  
//点到点距离   
double dist( point a, point b )  
{  
    return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));  
}   
  
//点到直线距离   
double dist( point p, point a, point b )  
{  
    return fabs(crossproduct( p, a, b )/dist( a, b ));  
}   
  
//坐标排序   
bool cmp1( point a, point b )  
{  
    return (a.x == b.x)?(a.y < b.y):(a.x < b.x);  
}  
  
//级角排序   
bool cmp2( point a, point b )  
{  
    double cp = crossproduct( P[0], a, b );  
    if ( cp == 0 ) return a.d < b.d;  
    else return cp > 0;  
}  
  
//叉乘判断平行    
double judge1( point a, point b, point c, point d )    
{    
    return crossproduct( a, b, point( a.x+d.x-c.x, a.y+d.y-c.y ) );  
}    
  
//点乘判断垂直   
double judge2( point a, point b, point c, point d )  
{  
    return ((b.x-a.x)*(d.x-c.x)+(b.y-a.y)*(d.y-c.y));  
}   
  
double Graham( int n )  
{  
    if ( n < 3 ) return 0.0;  
    sort( P+0, P+n, cmp1 );  
    for ( int i = 1 ; i < n ; ++ i )  
        P[i].d = dist( P[0], P[i] );  
    sort( P+1, P+n, cmp2 );  
      
    //计算凸包   
    int top = 1;  
    for ( int i = 2 ; i < n ; ++ i ) {  
        while ( top > 0 && crossproduct( P[top-1], P[top], P[i] ) < esp ) -- top;  
        P[++ top] = P[i];  
    }  
    P[++ top] = P[0];  
    if ( top < 3 ) return 0.0;  
      
    //旋转卡壳  
    int L2 = 0,L3 = 0,L4 = 0;  
    for ( int i = 0 ; i < top ; ++ i ) {  
        if ( P[i].y <= P[L2].y ) L2 = i;  
        if ( P[i].x >= P[L3].x ) L3 = i;  
        if ( P[i].y >= P[L4].y ) L4 = i;  
    }  
      
    double Min = (P[0].x-P[L3].x)*(P[L2].y-P[L4].y);  
    for ( int L1 = 0 ; L1 < top ; ++ L1 ) {  
          
        //旋转平行边   
        while ( judge1( P[L1], P[L1+1], P[L3], P[L3+1] ) > esp )  
            L3 = (L3+1)%top;  
          
        //旋转垂直边   
        while ( L2 != L3 && judge2( P[L1], P[L1+1], P[L2], P[L2+1] ) > esp )   
            L2 = (L2+1)%top;  
        while ( L4 != L1 && judge2( P[L1+1], P[L1], P[L4], P[L4+1] ) > esp )   
            L4 = (L4+1)%top;  
          
        double D = dist( P[L3], P[L1], P[L1+1] );  
        double L = dist( P[L2], P[L4], point( P[L4].x-P[L1+1].y+P[L1].y, P[L4].y+P[L1+1].x-P[L1].x ) );  
        if ( Min > D*L ) Min = D*L;  
    }  
    return Min;  
}  
  
int main()  
{  
    int n;  
    while ( ~scanf("%d",&n) && n ) {  
        for ( int i = 0 ; i < n ; ++ i )  
            scanf("%lf%lf",&P[i].x,&P[i].y);  
          
        printf("%.4lf\n",Graham( n ));  
    }  
    return 0;  
}  

 

 
补充:软件开发 , C++ ,
CopyRight © 2012 站长网 编程知识问答 www.zzzyk.com All Rights Reserved
部份技术文章来自网络,