求大侠指点：在eclipse里面用jdbc连接数据库出现问题
我写的代码：try{
Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");
}
catch(Exception e)
{
}
try{
url="jdbc:sqlserver://127.0.0.1:1433;DatabaseName=query";
user="sa";
pswd="sa";
select="select * from department where departmentName='"+departname+"')";
conn=DriverManager.getConnection(url,user,pswd);
sql=conn.createStatement();
re=sql.executeQuery(select);
while(re.next())
{
out.print("department is located:");
out.print("("+re.getInt(5)+","+re.getInt(6)+")");
}
conn.close();
}
catch(SQLException ee)
{
out.print(ee);
}
数据库名字为：query，表名为：departtment
运行结果在表单的下面出现了这样的问题：
com.microsoft.sqlserver.jdbc.SQLServerException: ')' 附近有语法错误
这是什么问题啊？ --------------------编程问答-------------------- 你那个sql多了 一个select="select * from department where departmentName=’"+departname+"‘";这样就对了 --------------------编程问答-------------------- 非常感谢，没有出现这个问题了 --------------------编程问答-------------------- 可以查询了，但是查询却没有什么结果，不知道是怎么回事？能帮我看下吗？
这是所有的代码：
SelectDepartment.jsp
<%@ page language="java" contentType="text/html; charset=GBK"
pageEncoding="GBK"%>
<%@ page import="java.sql.*" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=GBK">
<title>Show departments and transactions</title>
</head>
<body>
<form action ="" method = post name=form>
查找部门<input type ="text" name="departname" >
</input>
<input type ="submit" value="查询" name = "submit"></input>
</form>
<%
String departname = request.getParameter("departname");
String result="";
String url;
String user;
String pswd;
String select;
Connection conn;
Statement sql;
ResultSet re;
try{
Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");
}
catch(Exception e)
{
}
try{
url="jdbc:sqlserver://127.0.0.1:1433;DatabaseName=query";
user="sa";
pswd="sa";
select="select * from department where departmentName='"+departname+"'";
conn=DriverManager.getConnection(url,user,pswd);
sql=conn.createStatement();
re=sql.executeQuery(select);
while(re.next())
{
out.print("department is located:");
out.print("("+re.getInt(5)+","+re.getInt(6)+")");
}
conn.close();
}
catch(SQLException ee)
{
out.print(ee);
}
%>
</body>
</html> --------------------编程问答-------------------- 手动查询下看可有结果。
补充：Java , Eclipse
