当前位置:编程学习 > C/C++ >>

POJ 1905,3122,3273

  做了不想写解题报告,有点水。

POJ 1905:

卡精度的题目,WA到疯了。

代码:

[html] 
#include<cstdio> 
#include<cmath> 
using namespace std; 
 
const double eps = 1e-5; 
const double pi = acos(-1.0); 
 
int main() 

    double L, N, C; 
    while ( scanf("%lf%lf%lf",&L,&N,&C) ) 
    { 
        if (L < 0 && N < 0 && C < 0) break; 
        if (L==0 || N==0 || C==0) 
        { 
            printf("0.000\n"); 
            continue; 
        } 
        double Len = (1+N*C) * L; 
        double mid, left = 0, right = pi / 2; 
        double tmp, Sin, ret; 
        while ( 1 ) 
        { 
            mid = (left+right) / 2.0; 
            tmp = mid * L; 
            Sin = sin(mid); 
            if ( fabs(tmp-Len*Sin) < eps*Sin ) break; 
            if ( tmp > Len*Sin ) right = mid; 
            else left = mid; 
        } 
        ret = Len * (1-cos(mid)) / (2 * mid); 
        printf("%.3lf\n",ret); 
    } 
    return 0; 

POJ 3122  pie

代码:

[cpp] 
#include<iostream> 
#include<cmath> 
using namespace std; 
int r[10005]; 
#define PI 4*atan(1.0) 
#define maxn 10000 
int main() 

    int t,n,f; 
    scanf("%d",&t); 
    while( t--){ 
           scanf("%d%d",&n,&f); 
           memset(r,0,sizeof(r)); 
           for(int i=0;i<n;i++) scanf("%d",&r[i]); 
           double low=0,high=PI*maxn*maxn,mid; 
           while( high-low>0.0001){ 
                  mid=(low+high)/2;  
                  int cnt=0; 
                  for(int i=0;i<n;i++) 
                     cnt+=(int)floor(PI*r[i]*r[i]/mid); 
                  if(cnt<f+1) high=mid; 
                  else low=mid; 
           }  
           printf("%.4lf\n",low); 
    } 
    return 0; 

POJ 3273

代码:

[cpp]
#include<iostream> 
using namespace std; 
int a[100005],m,n; 
bool ok(int av) 

     int sum,i,j; 
     for( i=1,j=0;i<=m;i++){ 
             for(  sum=0;j<n;j++){ 
                     if(sum+a[j]>av) break; 
                     sum+=a[j]; 
             } 
             if(j==n) return true; 
     } 
     return false; 

int main() 

    int i,sum; 
    while( scanf("%d%d",&n,&m)!=EOF){ 
           sum=0; 
           for( i=0;i<n;i++){ 
                scanf("%d",&a[i]); 
                sum+=a[i]; 
           } 
           int lo=0,high=sum, mid; 
           while( lo<high){ 
                  mid=(lo+high)>>1; 
                  if( ok(mid)) 
                      high=mid; 
                  else lo=mid+1; 
           } 
           printf("%d\n",lo); 
    } 
    return 0; 

补充:软件开发 , C++ ,
CopyRight © 2022 站长资源库 编程知识问答 zzzyk.com All Rights Reserved
部分文章来自网络,