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HTTP Status 404 -

<?xml version="1.0" encoding="gb2312"?>
<web-app version="2.4" 
 xmlns="http://java.sun.com/xml/ns/j2ee" 
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
 xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
 http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
  <filter>
  <filter-name>struts2</filter-name>
  <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
  </filter>
  <filter-mapping>
   <filter-name>struts2</filter-name>
   <url-pattern>/*</url-pattern>
  </filter-mapping>
</web-app>
<%@ page language="java" import="java.util.*" pageEncoding="gb2312"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'login.jsp' starting page</title>
    
 <meta http-equiv="pragma" content="no-cache">
 <meta http-equiv="cache-control" content="no-cache">
 <meta http-equiv="expires" content="0">    
 <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
 <meta http-equiv="description" content="This is my page">
 <!--
 <link rel="stylesheet" type="text/css" href="styles.css">
 -->

  </head>
  
  <body>
         <form action="login.action" method="post">
                                          用户名:<input type="text" name="username"> 
                                             密 码:<input type="password" name="password">
                <input type="submit" value="提交">
         </form>
  </body>
</html>
出现这个错误是什么原因啊



--------------------编程问答-------------------- <form action="login.action" method="post">


检查一下action这里 --------------------编程问答-------------------- 是不是action没配置.或者跳转时,路径配置错误 --------------------编程问答-------------------- ⊙﹏⊙b汗 ==404==只能说明一件事 你的地址输入错误

只能默默祝楼主早日到达500错误....
补充:Java ,  非技术区
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