请教路过的大神，初识编程1个月，有关条件和各功能的调用问题，感激！
菜鸟新手本人有一个作业，在控制台下的程序集A> 摄氏、华氏间温度转换器
1>摄氏转华氏
2>华氏转摄氏
3>返回
B> 英尺、米长度转换器
1>foot&inch to cm
2>cm to foot&inch
3>返回
C> 迈、千米/时 速度转换器
1>kph to mph
2>mph to kph
3>返回
D> 油耗计算器
1>
2>
3>返回
E> Exit
（之前发帖问过一次，还被鄙视是野鸡大学。。呃，实在不是，是本人太菜。。现在有一些新的问题）
问题1：如何做到从次级菜单返回主菜单啊？求详细的语句……光知道用循环，不知道咋循环。。
还有作业要求每执行完一次运算，自动返回次级菜单，这个我也不会。。
问题2：运算中会提示是否显示另外一种计算结果在，这时需要用户输入"Y"来进行，是不是要将这个Y转化成bool来 判断是否进行下一个操作呢？请问如何实现呢？
问题3：用什么样的语句从主菜单调用各个function,这是我写的菜单代码：
string menu = "\n1> Temperature calculator"
+ "\n2> Length calculator"
+ "\n3> Speed calculator"
+ "\n4> Fuel consuption calculator"
+ "\n5> Exit program";
string menuOption,
subMenuOption,
TempCal,
LenthCal,
SpdCal,
FCCal;
Console.Write(menu);
Console.WriteLine(" \n\nPlease enter your option..");
menuOption = Console.ReadLine();
switch (menuOption)
{
case "1": menuOption = TempCal ;
break;
case "2": menuOption = LenthCal;
break;
case "3": menuOption = SpdCal;
break;
case "4": menuOption = FCCal;
break;
case "5": return;
default: Console.WriteLine("Please enter a valid menu option");
break;
}
比如case 4，怎么做可以直接跳到油耗计算器去啊？
各个function之间应当保持什么样的关系呢？ 每个function的heading该怎么写？ static void什么的吗？
最后是我写的油耗计算器，里面有好多语句不通过>_<! 希望老鸟们猛烈批评指点……
static void Main(string[] args)
{
string readGallonOrLitre,
inputFuelUsed,
inputDistanceTravelled,
seeEqvltResult;
double fuelUsedGallon,
fuelUsedLitre,
distanceTravelledMile,
distanceTravelledKM,
fuelConsptMile,
fuelConsptKilo;
int
gallonOrLitre;
bool y;
const double KILOS_PER_MILE = 1.61,
MILES_PER_KILO = 0.62,
GALLON_PER_LITRE = 0.26,
LITRE_PER_GALLON = 3.76;
Console.WriteLine("Please select your prefered measurement...");
Console.WriteLine("\nFor British imperial measure ( gallon and miles), please enter 1");
Console.WriteLine("For metric measure ( kilometres and litre), please enter 2");
Console.Write("\nNow please enter your option: ");
readGallonOrLitre = Console.ReadLine();
gallonOrLitre = int.Parse(readGallonOrLitre);
switch (gallonOrLitre)
{
case 1:
Console.Write("Please enter the amount of fuel used: ");
inputFuelUsed = Console.ReadLine();
fuelUsedGallon = double.Parse(inputFuelUsed);
Console.Write("Please enter the distance travelled: ");
inputDistanceTravelled = Console.ReadLine();
distanceTravelledMile = double.Parse(inputDistanceTravelled);
fuelConsptMile = distanceTravelledMile / fuelUsedGallon;
Console.WriteLine("Fuel consumption is " + fuelConsptMile + " gallons per mile");
Console.WriteLine("\nDo you want to see the equivalent result in liters per 100 kilomitres? \nIf yes enter y; if not enter anything to go back.");
seeEqvltResult = Console.ReadLine();
y = Convert.ToBoolean(seeEqvltResult);
fuelConsptKilo = distanceTravelledMile * KILOS_PER_MILE / fuelUsedGallon * LITRE_PER_GALLON;
if (y)
{
Console.WriteLine("Your current fuel consumption is {0} per 100 kilometres", fuelConsptKilo);
}
else
return;
break;
case 2:
Console.Write("Pleased enter the amount of fuel used: ");
inputFuelUsed = Console.ReadLine();
fuelUsedLitre = double.Parse(inputFuelUsed);
Console.Write("Please enter the distance travelled: ");
inputDistanceTravelled = Console.ReadLine();
distanceTravelledKM = double.Parse(inputDistanceTravelled);
fuelConsptKilo = distanceTravelledKM / fuelUsedLitre;
Console.WriteLine("Fuel consumption is " + fuelConsptKilo + " litres per kilometre");
Console.WriteLine("\nDo you want to see the equivalent result in gallons per 100 miles? \nIf yes enter y; if not enter anything to go back.");
seeEqvltResult = Console.ReadLine();
y = Convert.ToBoolean(seeEqvltResult);
fuelConsptMile = distanceTravelledKM * MILES_PER_KILO / fuelUsedLitre * GALLON_PER_LITRE;
if (y)
{
Console.WriteLine("Your current fuel consumption is {0} per 100 kilometres", fuelConsptMile);
}
else
return;
break;
最后的最后，如果有哪位大大愿意无私多帮助我一些，可以具体看看我写好的东西喝作业要求，在这里
https://drive.google.com/folderview?id=0B6tnQDOeCTi0VVJjbVc5Sjk2RTA&usp=sharing
编程 条件 功能 --------------------编程问答-------------------- 拜谢，跪谢！！ --------------------编程问答-------------------- 同学，有那么麻烦么。我觉得一屏幕代码就足够了。 --------------------编程问答--------------------
易做图！实在是新手，理念能明白，伪代码能看懂，就是憋不出来。。。
要是能劳烦给写一遍，绝对恍然大悟啊，求指点。。。 --------------------编程问答-------------------- 这是你写的第几个程序啊？ --------------------编程问答--------------------
易做图程序。。。。。。。。。。。。。 --------------------编程问答-------------------- 我只是逛逛论坛，不会C#。同求大神出来帮你解答。 --------------------编程问答-------------------- 没注释，无语 --------------------编程问答--------------------
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
class Command
{
public char CommandKey { get; set; }
public string CommandName { get; set; }
public string InputPrompt { get; set; }
public string OutputPrompt { get; set; }
public Func<double, double> Action { get; set; }
}
class Menu
{
public char CommandKey { get; set; }
public string CommandName { get; set; }
public List<Command> Commands { get; set; }
}
class Program
{
static void Main(string[] args)
{
List<Menu> mainMenu = new List<Menu>()
{
new Menu()
{
CommandKey = 'A',
CommandName = "摄氏、华氏间温度转换器",
Commands = new List<Command>()
{
new Command() { Action = x => 32.0 + x * 1.8, CommandKey = '1',
CommandName = "摄氏转华氏", InputPrompt = "请输入摄氏温度：",
OutputPrompt = "{0}C = {1}F." },
new Command() { Action = x => (x - 32.0) / 1.8, CommandKey = '2',
CommandName = "华氏转摄氏", InputPrompt = "请输入华氏温度：",
OutputPrompt = "{0}F = {1}C." }
}
},
new Menu()
{
CommandKey = 'B',
CommandName = "英尺、米长度转换器",
Commands = new List<Command>()
{
new Command() { Action = x => x * 2.54, CommandKey = '1',
CommandName = "foot&inch to cm", InputPrompt = "请输入inch：",
OutputPrompt = "{0}inch = {1}cm." },
new Command() { Action = x => x / 2.54, CommandKey = '2',
CommandName = "cm to foot&inch", InputPrompt = "请输入cm：",
OutputPrompt = "{0}cm = {1}inch." }
}
},
new Menu()
{
CommandKey = 'C',
CommandName = "迈、千米/时 速度转换器",
Commands = new List<Command>()
{
new Command() { Action = x => x * 1.609344, CommandKey = '1',
CommandName = "mph -> kmph", InputPrompt = "请输入mph：",
OutputPrompt = "{0}mph = {1}kmph." },
new Command() { Action = x => x / 1.609344, CommandKey = '2',
CommandName = "kmph -> mph", InputPrompt = "请输入kmph：",
OutputPrompt = "{0}kmph = {1}mph." }
}
},
new Menu()
{
CommandKey = 'D',
CommandName = "油耗计算器",
Commands = new List<Command>()
}
};
string inputKey = "";
char exitKey = (char)(mainMenu.Max(x => x.CommandKey) + 1);
while (inputKey != exitKey.ToString())
{
Console.Clear();
Console.WriteLine("=====Main Menu=====");
foreach (var menu in mainMenu)
{
Console.WriteLine("{0}> {1}", menu.CommandKey, menu.CommandName);
}
Console.WriteLine("{0}> {1}", exitKey, "Exit");
inputKey = Console.ReadLine().ToUpper();
if (mainMenu.Any(x => x.CommandKey == inputKey.FirstOrDefault()))
{
Menu menu = mainMenu.First(x => x.CommandKey == inputKey.FirstOrDefault());
char returnKey = (char)(menu.Commands.Select(x => x.CommandKey).DefaultIfEmpty('0').Max() + 1);
inputKey = "";
while (inputKey != returnKey.ToString())
{
Console.Clear();
foreach (var cmd in menu.Commands)
{
Console.WriteLine("{0}> {1}", cmd.CommandKey, cmd.CommandName);
}
Console.WriteLine("{0}> {1}", returnKey, "Return");
inputKey = Console.ReadLine().ToUpper();
if (menu.Commands.Any(x => x.CommandKey == inputKey.FirstOrDefault()))
{
Command cmd = menu.Commands.First(x => x.CommandKey == inputKey.FirstOrDefault());
Console.Write(cmd.InputPrompt);
double input = double.Parse(Console.ReadLine());
Console.WriteLine(cmd.OutputPrompt, input, cmd.Action(input));
Console.ReadKey();
inputKey = returnKey.ToString();
}
}
inputKey = "";
}
}
}
}
}
补充：.NET技术 , C#
