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Palindrome Number @LeetCode

package Level2;

/**
 *
 * Palindrome Number
 * 
 * Determine whether an integer is a palindrome. Do this without extra space.

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Some hints:
Could negative integers be palindromes? (ie, -1)

If you are thinking of converting the integer to string, note the restriction of using extra space.

You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case?

There is a more generic way of solving this problem.
 */
public class S9 {

	public static void main(String[] args) {
		System.out.println(isPalindrome(10101));
	}

	public static boolean isPalindrome(int x) {
		int digits = 0;
        int tmp = x;
        // 算出位数
        while(tmp != 0){
        	tmp /= 10;
        	digits++;
        }
        int div = (int) Math.pow(10, digits-1);
	    return rec(x, div); 
    }
	
	// 递归比较
	public static boolean rec(int x, int div) {
		if(x < 0){		// 负数
        	return false;
        }
        if(x < 10){		// 一位数
        	return true;
        }
       
        int quotient = x / div;		// 最高位
        int remainder = x % 10;	// 最低位
        if(quotient != remainder){
        	return false;
        }
        
        // 更新除数和被除数
        return rec((x-quotient*div-remainder)/10, div/100); 
	}
	
}

 

补充:软件开发 , Java ,
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