[每日一题] OCP1z0-047 :2013-07-21子查询――多字段的顺序
[每日一题] OCP1z0-047 :2013-07-21子查询――多字段的顺序
查和104号员工同一个部门和同一个经理的所有员工的员工编号、姓名和部门。
hr@OCM> SELECTemployee_id,first_name,department_id 2 FROMemployees 3 WHERE (manager_id,department_id) = (SELECT department_id,manager_id FROM 4 employees 5 WHERE employee_id=104) 6 ANDemployee_id<.104; no rows selected
用上面的语句,没有查出记录来。原来是什么呢?主要是where条件这里的子查询的操作符或字段的顺序写错了!我们来分析答案:
答案A是把这语句改成:exists的语法不是这样写的,明显不对!!!
hr@OCM> SELECTemployee_id,first_name,department_id 2 FROMemployees 3 WHERE (manager_id,department_id) exists (SELECT department_id,manager_idFROM 4 employees 5 WHERE employee_id=104) 6 ANDemployee_id<>104; WHERE(manager_id,department_id) exists (SELECT department_id,manager_id FROM * ERROR at line 3: ORA-00920: invalidrelational operator
答案B把这语句改成:结果显示无记录,其实这语法是没问题的,只是where条件主查询字段顺序不匹配,所以答案B不正确
hr@OCM> SELECTemployee_id,first_name,department_id 2 FROMemployees 3 WHERE (manager_id,department_id) in (SELECT department_id,manager_idFROM 4 employees 5 WHERE employee_id=104) 6 ANDemployee_id<>104; no rows selected
答案C把这语句改成:结果显示无记录,其实这语法是没问题的,只是where条件主查询字段顺序不匹配,,所以答案C不正确
hr@OCM> SELECTemployee_id,first_name,department_id 2 FROMemployees 3 WHERE (manager_id,department_id) = any (SELECT department_id,manager_idFROM 4 employees 5 WHERE employee_id=104) 6 ANDemployee_id<>104; no rows selected
答案D把这语句改成:显示三条记录,OK,那就是答案D,WHERE后面字段的顺序严格要和子查询里的字段顺序要一致。
hr@OCM> SELECTemployee_id,first_name,department_id 2 FROMemployees 3 WHERE (manager_id,department_id) = (SELECT manager_id,department_id FROM 4 employees 5 WHERE employee_id=104) 6 ANDemployee_id<>104; EMPLOYEE_IDFIRST_NAME DEPARTMENT_ID ------------------------------- ------------- 105 David 60 106 Valli 60 107 Diana 60
最后正确答案是选:D