制作一个简单的服务器端控制
2000082805.aspx-------------------------------------------------------------
<%@ Register TagPrefix="CJ" Namespace="cjServerControls" %>
<html>
<head>
</head>
<body>
<form method="post" action="2000082605.aspx" runat="server">
<CJ:xmlDocReader listText="au_id" listValue="au_id" runat="server"
path="C:InetpubwwwrootmyASP utorialsauthors.xml" />
</form>
</body>
</html>
2000082805a.cs
-------------------------------------------------------------
using System;
using System.Data;
using System.IO;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
namespace cjServerControls
{
public class xmlDocReader : Control, INamingContainer
{
string _xmlPath;
string _listID;
string _listValue;
public string Path
{
get { return _xmlPath; }
set { _xmlPath = value; }
}
public string listText
{
get { return _listID; }
set { _listID = value; }
}
public string listValue
{
get {return _listValue; }
set {_listValue = value; }
}
//Were are creating a member here so we can access it throughout the class
DropDownList _DDL;
DataGrid _DG;
FileStream fs;
StreamReader sr;
DataSet ds;
protected override void PreRender()
{
if (Page.IsPostBack) {
DataView dv = new DataView(ds.Tables[0]);
dv.RowFilter = listValue + "='" + _DDL.SelectedItem.Text + "'";
_DG = new DataGrid();
_DG.DataSource = dv;
_DG.DataBind();
Controls.Add(_DG);
}
}
protected override void CreateChildControls()
{
fs = new FileStream(Path, FileMode.Open, FileAccess.Read);
sr = new StreamReader(fs);
ds = new DataSet();
补充：asp教程,ASP入门
