android中解析服务器发过来的JSON数据

	 

	解析ＪＳＯＮ的效率要比ｘｍｌ高很多，建议在开发中，数据不是很复杂就用ＪＳＯＮ传输数据

	 

	public class VideoService { 

	    public List<Video> getJsonVieos() throws IOException, JSONException{ 

	        String path = "http://111.14.19.37:8080/vidoe/video/list.do?format=json"; 

	        URL url = new URL(path); 

	        HttpURLConnection conn = (HttpURLConnection) url.openConnection(); 

	        conn.setConnectTimeout(5 * 1000); 

	        conn.setRequestMethod("GET"); 

	        InputStream is = conn.getInputStream(); 

	        byte[] data = InputStreamUtil.getByteArray(is);／／用自己写的工具类把流转成ｂｙｔｅ数组 

	        String json = new String(data); 

	        JSONArray array = new JSONArray(json); 

	        List<Video> videos = new ArrayList<Video>(); 

	        for(int i = 0; i<array.length(); i++){ 

	            JSONObject jo = array.getJSONObject(i); 

	            int id = jo.getInt("id"); 

	            String title = jo.getString("title"); 

	            int timelength = jo.getInt("timelength"); 

	            videos.add(new Video(id, title, timelength)); 

	        } 

	        return videos; 

	    } 

	}   

	摘自：com360 博客

补充：移动开发 , Android ,

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