当前位置:编程学习 > php >>

php中将时间差转换为字符串提示的实现代码

答案: 如微博

这看起来更加人性化,好吧,上代码
复制代码 代码如下:

<?php
class timeAgo
{
static $timeagoObject;
private $rustle;
private $unit;

private function __construct()
{

}
private function __clone(){ }
public static function getObject()
{
if(! (self::$timeagoObject instanceof self) )
self::$timeagoObject = new timeAgo();

return self::$timeagoObject;
}
private function count_int($unix_C) // main function
{
if(! (isset($unix_C) || is_numeric($unix_C)) )
return 'don\'t find parameter';

$d = time()-$unix_C ; // $d - unix time difference value
$d_int =(int)floor($d/60) ; // minimum unit -- minutes unix/60

$this->unit = 0 ; // is minutes,hour or day?

if($d_int < 60){ // minutes in one hour 3600
$this->rustle = $d_int;
$this->unit = 1;
}
else if($d_int < 720){ //hour in one day 3600*12
$this->rustle = floor($d_int/60);
$this->unit = 2 ;
}
else if($d_int < 7200){ //day in ten days 3600*12*10
$this->rustle = floor($d_int/720);
$this->unit = 3 ;
}
else{
$this->rustle = $d ;
$this->unit = 4 ;
}
}
public function piece_str($C)
{
$this->count_int($C);

$u = '';
switch( $this->unit )
{
case 1:
$u = 'minute';
break;
case 2:
$u = 'hour';
break;
case 3:
$u = 'day';
break;
case 4:
$u = '';
break;
case 0:
return 'sorry , get time is fail';
}
if($this->unit < 4)
{
if($this->rustle > 1)
return (string)$this->rustle.$u.'s ago';
else if($this->rustle == 1)
return (string)$this->rustle.$u.'ago';
else
return 'Just now';
}
}
/* example: $ago = timeAgo::getObject();
* echo $ago->piece_str($unix);
* // 2 days ago
*/
}
?>

上一个:PHP header函数分析详解
下一个:PHP 防注入函数(格式化数据)

CopyRight © 2012 站长网 编程知识问答 www.zzzyk.com All Rights Reserved
部份技术文章来自网络,