C#编程实现a=8,b=68利用引用传递的方式实现a,b值的互换。

用C#编程实现a=8,b=68利用引用传递的方式实现a,b值的互换。

答案：using System;
class Swap
{
   static void SwapByRef(ref int a,ref int b)
    {
              intt;
              t=a;
              a=b;
              b=t;
    }
       
   public static void Main()
    {            
       int a = 8,b=68;
       Console.Write("a=");
              Console.WriteLine(a);
       Console.Write("b=");
              Console.WriteLine(b);
       SwapByRef(ref a,ref b);
       Console.Write("a=");
              Console.WriteLine(a);
       Console.Write("b=");
              Console.WriteLine(b);
    }
}
static void jiaohuan(ref int num1,ref int num2)
    {
              int temp=num1;
              num1=num2;
              num2=temp;
    }
static void Main(string[] args)
{
            int num1=10;
            int num2=20;
            Console.WriteLine("交换前num1={0},num2={1}",num1,num2);
            jiaohuan(ref num1, ref num2);
            Console.Write("交换后num1={0},num2={1}", num1, num2);
            Console.Read();
}
 
OK复制去看看是不是你要的

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